Factor completely 2c^5 + 44c^4 + 242c^3
2 answers:
2c^5 + 44c^4 + 242c^3
Take out common factors.
= 2c^3(c^2 + 22c + 121)
( Refer for attachment for next step )
= 2c^3(c + 11)(c + 11)
= 2c^3(c + 11)^2
<span> 2c^5 + 44c^4 + 242c^3
Take </span>2 <span>c^3 common:</span><span>
2 c^3 (c^2 + 22 c + 121)
Factorize the quadratic part:
</span>2 c^3 (c^2 + 22 c + 121<span>)
</span>2 c^3 (c+11)(c+11)
Answer
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Answer:
(3+5) = 8 times 8 = 64 64+(8-11)+Z=64+(-3) + Z=62+z= 62+2 = 64
64
Step-by-step explanation:
Its an equilateral triangle so all sides are equal.
2x + 5 = 4x - 1
5 = 2x - 1
6 = 2x
3 = x
Do you get it?
Multiply all the numbers together to get your answer.
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Wait what’s j I’m confused
