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Triss [41]
3 years ago
7

Factor completely 2c^5 + 44c^4 + 242c^3

Mathematics
2 answers:
Olenka [21]3 years ago
5 0
2c^5 + 44c^4 + 242c^3

Take out common factors.

= 2c^3(c^2 + 22c + 121)

( Refer for attachment for next step )

= 2c^3(c + 11)(c + 11)

= 2c^3(c + 11)^2

iVinArrow [24]3 years ago
3 0
<span> 2c^5 + 44c^4 + 242c^3
Take </span>2 <span>c^3 common:</span><span>
2 c^3 (c^2 + 22 c + 121)
Factorize the quadratic part:
</span>2 c^3 (c^2 + 22 c + 121<span>)
</span>2 c^3 (c+11)(c+11)
Answer

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Answer:

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