2 years ago

Factor completely 2c^5 + 44c^4 + 242c^3

2 answers:

5 0

2c^5 + 44c^4 + 242c^3

Take out common factors.

= 2c^3(c^2 + 22c + 121)

( Refer for attachment for next step )

= 2c^3(c + 11)(c + 11)

= 2c^3(c + 11)^2

iVinArrow [24]2 years ago

3 0

2c^5 + 44c^4 + 242c^3
Take 2 c^3 common:
2 c^3 (c^2 + 22 c + 121)
Factorize the quadratic part:
2 c^3 (c^2 + 22 c + 121)
2 c^3 (c+11)(c+11)
Answer

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