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olchik [2.2K]
3 years ago
11

Mary Alice is trying to answer the question. How many siblings does each member of her 30 person Biology class have. What is the

best way to determine this?
A) Take a sample of 10 members of the class and then find the mean of the responses.

B) Survey each member of her 30 person class to determine how many siblings each person has.

C) Take a survey from the entire school and then look at the responses from students in a Biology class.

D) Look at the school enrollment roster to see how many siblings each member of the class has at the school.
Mathematics
2 answers:
VladimirAG [237]3 years ago
4 0
B
The other answers wouldn't help that much. 
vagabundo [1.1K]3 years ago
4 0

B) Survey each member of her 30 person class to determine how many siblings each person has.

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Kay [80]

Answer:

Las cantidades empleadas para su preparación son: 15 onzas de solución al 20 % y 35 onzas de solución al 40 %.

Step-by-step explanation:

Podemos estimar la proporción de ingredientes mediante el siguiente promedio ponderado:

0.34= \frac{0.2\cdot m_{A} + 0.4\cdot m_{B}}{m_{A}+m_{B}} (1)

Donde:

m_{A} - Masa de la solución al 20 %, en onzas.

m_{B} - Masa de la solución al 40 %, en onzas.

Podemos simplificar la formula como sigue:

0.2\cdot x + 0.4\cdot (1-x) = 0.34 (2)

Donde x es la proporción de la solución al 20 % dentro de la solución final, sin unidades.

Ahora resolvemos para x en (2):

0.4-0.2\cdot x = 0.34

0.2\cdot x = 0.06

x = \frac{0.06}{0.2}

x = 0.3

Este resultado quiere decir que la solución al 34 % es el resultado de 30 % de la solución al 20 % y 70 % de la solución al 40 %. Si conocemos que la solución final tiene una masa de 50 onzas, entonces las cantidades empleadas para su preparación son: 15 onzas de solución al 20 % y 35 onzas de solución al 40 %.

4 0
3 years ago
Help please this question is confusing
lisabon 2012 [21]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
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Find the numerical value of the log expression. \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3 loga=7logb=10logc=3 \log \
bija089 [108]

Answer:

  32

Step-by-step explanation:

  \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3\\\\ \log \dfrac{a^8c^2}{b^3}=8\log{a}+2\log{c}-3\log{b}=(8)(7)+(2)(3)-(3)(10)\\\\=56+6-30=\boxed{32}

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The applicable rules of logarithms are ...

  log(ab/c) = log(a) +log(b) -log(c)

  log(a^b) = b·log(a)

6 0
3 years ago
A group of friends were working on a student film. They spent all their budget on props and costumes. They spent $693 on props,
sergeinik [125]

Answer:

The total budget is $1260

Step-by-step explanation:

Given

Props = \$693

Costumes = 45\%

Required

Determine the total budget

Since all budgets was spent on Props and Costumes only.

We have that.

\%Props + \%Costumes = 100\%

\%Props + 45\%= 100\%

\%Props= 100\% -45\%

\%Props= 55\%

In other words, 55% was spent on Props

Let the total budget be x, we have:

55\% * x = \$693

Make x the subject

x = \$693/55\%

x = \$1260

Hence, the total budget is $1260

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What is the least common multiple of 8 and 18?<br> A<br> 16<br> B<br> 36<br> С<br> 72<br> D<br> 144
Verdich [7]

Answer:72

Step-by-step explanation:

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3 years ago
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