
. Subtract 10x from both sides.

. Divide by 5 on both sides. x=20. So you would need to buy 20 movies.
<h3>
Answers:</h3>

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Explanation:
The scale factor is 2, which means we double each coordinate of each point. The general rule is
with k = 2. So we can say the more specific dilation rule is 
Something like W(-2,2) moves to W ' (-4, 4) after multiplying each coordinate by 2. Do the same for the other points as well.
The given preimage points
- V = (-2, -1)
- W = (-2, 2)
- X = (0, 2)
- Y = (3, -1)
will dilate to the corresponding image points
- V ' = (-4, -2)
- W ' = (-4, 4)
- X ' = (0, 4)
- Y ' = (6, -2)
as shown below. This causes the image to be larger compared to the preimage (since the scale factor is larger than 1). Any given point is twice as far from the origin as compared to before, which in turn means the distance between any two points is twice as much.
Answer:
6x+20
c.
Step-by-step explanation:
If f(x)=6x+2 and you are asked to find f(x+3), then you just replace all the x's in f(x)=6x+2 with (x+3).
Doing this gives you:
f(x)=6x+2 with new input (x+3) in place of out input (x)
f(x+3)=6(x+3)+2
f(x+3)=6x+18+2
f(x+3)=6x+20
Answer:
First, write 80% as 80100. Then write an equivalent ratio that has the answer in the numerator and 200 in the denominator. 100 x 2 is 200, so 80 x 2 will be the answer. 80 x 2 = 160. The answer is $160.