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LUCKY_DIMON [66]
2 years ago
10

Express 30^2/3 into the simplest radical form? Thanks :)

Mathematics
1 answer:
Dafna11 [192]2 years ago
4 0

Answer:

9.65

Step-by-step explanation:

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A rancher has 200 feet of fencing to enclose two adjacent corrals
Arturiano [62]

Answer:

a) Each corral should be 33⅓ ft long and 25 ft wide

b) The total enclosed area is 1666⅔ ft²

Step-by-step explanation:

I assume that the corrals have identical dimensions and are to be fenced as in the diagram below

Let x = one dimension of a corral

and y = the other dimension

 

(a) Dimensions to maximize the area

The total length of fencing used is:

4x + 3y = 200

4x = 200 – 3y

x = 50 - ¾y

The area of one corral is A = xy, so the area of the two corrals is

A = 2xy

Substitute the value of x

A = 2(50 - ¾y)y

A = 100 y – (³/₂)y²

This is the equation for a downward-pointing parabola:

A = (-³/₂)y² + 100y

a = -³/₂; b = 100; c = 0

The vertex (maximum) occurs at  

y = -b/(2a)  = 100 ÷ (2׳/₂) = 100 ÷ 3 = 33⅓ ft  

4x + 3y = 100

Substitute the value of y

4x + 3(33⅓) = 200

4x + 100 = 200

4x = 100  

x = 25 ft

Each corral should measure 33⅓ ft long and 25 ft wide.

Step 2. Calculate the total enclosed area

The enclosed area is 50 ft long and 33⅓ ft wide.

A = lw = 50 × 100/3 = 5000/3 = 1666⅔ ft²

6 0
2 years ago
15) Brenda walked 12.2 miles to raise money for her local food pantry. She
ExtremeBDS [4]

Answer:

542.9

Step-by-step explanation:

Please mark brainliest

6 0
3 years ago
Read 2 more answers
Calcula el ancho de un terreno rectangular si el largo mide 20 metros y la superficie es de 280 metros cuadrados
Anna35 [415]

Answer:14 m

Step-by-step explanation:

Dada

larga l=20\ m

superficie A=280\ m^2

Suponga que el ancho es w

La superficie está dada por el producto de la longitud y la anchura.

\therefore A=lw\\\Rightarrow 280=20\times w\\\Rightarrow w=14\ m

Por lo tanto, el ancho es de 14 m.

4 0
3 years ago
Help please I’ll give brainleiest :)
Paladinen [302]

Answer:

1 hour would be 10 $ each

Step-by-step explanation:

1)$10

2)$50

3)$80

I hope this helps

4 0
2 years ago
Diff Eq dy/dx= (ycos(x))/(1+y^2) initial condition is y(0)=1 work below ...?
Volgvan
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
5 0
3 years ago
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