A 7/16 inch long bolt is used in a machine.What is this length written as a decimal?

Helpppp im giving brainiest to the first answer <3333

ahrayia [7]

Answer:

A horse ranch offers guests the choice of 8 different horses. They can also choose to ride bareback or with a saddle. Finally, there are 3 different paths to ride on. How many different ways can guests make their selection?

Step-by-step explanation:

sorry if im wrong

7 0

3 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

4 years ago

Monica’s retirement party cost two dollars, plus an additional three dollars for every guess she invites. If there are 16 guests

lesya692 [45]

Answer:

TWO BUCKS?? ballin on a budget

anyways, if there are 16 guests, the party would cost $50. sounds a lot more correct lol

8 0

3 years ago

Is there any tutors orrr

Papessa [141]

There’s tutors for math i just asked a tutor for help lol

4 0

3 years ago

Read 2 more answers

Eva wants to make two pieces of pottery.She needs 3/5 pound of clay for one piece and 7/10 pound of clay for the other piece.She

marta [7]

Answer:

a) Eva will need 2 bags of clay to make both pieces of pottery.

b) She will have leftover $\frac{11}{10}$ pounds of clay.

Step-by-step explanation:

Hi

a) We have to find the total amount of clay, as she needs $\frac{3}{5}pound=P_{1}$ and $\frac{7}{10}pound=P_{2}$ , so $P_{1}+P_{2}= \frac{3}{5} +\frac{7}{10} =\frac{6+7}{10}=\frac{13}{10}pounds$ , is the total amount of clay. Then as we Know that one bag of clay has $\frac{4}{5} =\frac{8}{10} pounds$ , It isn´t enough, but with two bags $2*\frac{8}{10}=\frac{16}{10} pounds$ , It is enough clay.

b) She will have leftover $\frac{16}{10} -\frac{13}{10} =\frac{3}{10}pounds$ of the second bag, then we add the third one, so $\frac{3}{10} +\frac{8}{10} =\frac{11}{10}pounds$ are leftover.

6 0

3 years ago