Answer: <em>5/8, i think :)</em>
Answer:
0.025
Step-by-step explanation:
-This is a conditional probability problem.
-Let L denote lens defect and C charging defect.
#We first calculate the probability of a camera having a lens defect;

#Calculate the probability of a camera having a charging defect:

The the probability that a camera has a lens defect given that it has a charging defect is calculated as:

Hence, the probability that a camera has a lens defect given that it has a charging defect is 0.025
Answer:
The answer is A or the first one
Step-by-step explanation:
This is because the domain is signifying the x amounts. So, this line keeps going on and on, which is all real numbers. On the other hand, the range are the y’s. The y’s are staying on the -100 line or above.
Answer:
he bought 5 peaches 2 bananas
Step-by-step explanation: