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Leona [35]
3 years ago
14

Please help me with this

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Hey!

---------------------------------------

Solution:

= 4(x + 3) - 1

= 4x + 12 - 1

= 4x + 11

---------------------------------------

Answer:

Jesse was on the right track at the beginning but she didn't use distributive property correctly. What she need to do was multiply 4 * x and 4 * 3 but she only did 4 * x.

---------------------------------------

Hope This Helped! Good Luck!

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in febuary you have a balance of $270 in your bank account. each month you deposit $45. let january=1, febuary=2 and so on. brai
Lynna [10]

Answer:

 $450 in June

Step-by-step explanation:

$X = 270 + 45 × ( number of month)  

In this problem, February, the month you start with, would be month 0.

June would be 4.

$X = 270 + 45 × 4

= 270 + 180

= $450 in June

3 0
3 years ago
Theme-and-variations form may be schematically outlined as ______.
lions [1.4K]
<span>Theme-and-variations form may be schematically outlined as </span>AA'A''A'''A''''.

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A spring coat that cost $60.00 was marked up 20% of the cost. What was the price increase?
Irina18 [472]

The price increase was $12.  

  60

x 0.2  

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7 0
3 years ago
Read 2 more answers
Adam And Eve had 32 apple in 8 barrels how many would they have in all?
astraxan [27]

Answer:

Adam and Eve will have 4 apples in each barrel

Step-by-step explanation:

32/8

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7 0
2 years ago
How do I find the restrictions on x if there are any? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%20-%201%7D%20%20%3
Natali5045456 [20]

We have the expression:

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When we have rational functions, where the denominator is a function of x, we have a restriction for the domain for any value of x that makes the denominator equal to 0.

That is because if the denominator is 0, then we have a function f(x) that is a division by zero and is undefined.

If we have a value that makes f(x) to be undefined, then this value of x does not belong to the domain of f(x).

Expression:

\begin{gathered} \frac{1}{x-1}=\frac{5}{x-10} \\ \frac{x-1}{1}=\frac{x-10}{5} \\ x-1=\frac{x}{5}-\frac{10}{5} \\ x-1=\frac{1}{5}x-2 \\ x-\frac{1}{5}x=-2+1 \\ \frac{4}{5}x=-1 \\ x=-1\cdot\frac{5}{4} \\ x=-\frac{5}{4} \end{gathered}

Answer: There is no restriction for x in the expression.

6 0
1 year ago
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