The answer is C: How long does it take distilled water to evaporate from a 5” diameter container?
Answer: The concentrations of
at equilibrium is 0.023 M
Explanation:
Moles of
= 
Volume of solution = 1 L
Initial concentration of
= 
The given balanced equilibrium reaction is,

Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5Ctimes%20%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Now put all the given values in this expression, we get :

By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of
at equilibrium is 0.023 M
a) Answer:
= 210,000 gram or 210 Kg
Explanation:
14 hr is equivalent to;
= 14 × 3600 s
But;
8.2x10^4 A = 8.2x10^4 Coulomb /second = 8.2x10^4 C/s
1 Faraday = 96485C
Molar mass of Li: 6.941 g/mol
Therefore;
{(8.2x10^4 C/s)×(14×3600s)×(6.941 g/mol)/(96485C/mol)}×70%
= 2.1x10^5 gram or 210 kg
b. Answer;
= 0.23 kWh/mol
Explanation and solution;
Energy per mole is given by;
(96485C/mol) × (8.4V) = 8.10x10^5 (J/mol)
= 8.10x10^5 (Ws/mol)
Divide by 3600s/h to get:
= 8.10x10^5 (Ws/mol)
= 225 Wh/mol
= 0.23 kWh/mol