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Inga [223]
3 years ago
14

Use the periodic table to answer the questions below.

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
7 0
The second is the answer. ⬆⬇⬆⬇⬆⬆⬆
Vera_Pavlovna [14]3 years ago
3 0
The three of them have the same amount of electrons, so we can’t determine the right one on that ground. As you might know, Pauli said that electrons are always in the position of the lowest energy. So the first situation is impossible because there is a free place available that takes less energy. Then the 3rd situation is nor possible because if one electron has a different spin than the others, there is a magnetic obstruction that be prevented if the spin changes. This means that the second situation is the right one.
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What is the charge on an ion that has an atomic number of 16 and contains 14e-?
lora16 [44]
The answer would be 2+ since the atomic number represents how many protons are in the element. In this case, there are 16 protons, but only 14 electrons, which means there are an additional 2 protons, hence the 2+ charge on the ion.
3 0
3 years ago
Answer will mark bl plz
lesya692 [45]

Answer:

A

Explanation:

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3 0
4 years ago
Name 2 animals that’s are omnivores give an example of a plant and an animal that each one might eat
denis-greek [22]

OMG THERE'S SPIDER BEHIND YOU!!! jk XD lets get back to the question.....

example of omnivores would be us humans but since you said ANIMALS then :

BEARS - bears are omnivores they feed on meat like fish and plants like grass or dandelion.

RACCOONS - their omnivores too they feed on meat like rats (ew), fish, frogs..etc they also eat plants like any kind fruit, grains, nuts ( i dont think all kind tho).

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6 0
4 years ago
Read 2 more answers
The metals in Groups 1A, 2A, and 3A ____.
choli [55]
All of these metals from cations, so they lost electrons when forming ions. The answer is D.
3 0
3 years ago
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Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

6 0
3 years ago
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