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2 years ago

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Chemistry

1 answer:

erastovalidia [21]2 years ago

8 0

hi have a nice day

will be less than 26 °C as water has a relatively higher specific heat than sand.

Explanation:

The specific heat of a substance is the amount of heat energy absorbed by one unit of mass of the substance when its temperature increases one unit.

From that, you can derive the equation for the specific heat of a substance:

specific heat = heat / (mass × ΔT)

Thus, assuming that all the heat provided by the lamp to both samples is the same and, as given, the amount (mass) of both samples is also the same, you have that the specific heat of the samples will be:

specific heat = constant / ΔT

So, specific heat and ΔT are inversely related.

It is known that water has a higher specific heat than sand (that is why the sand on the shore of a beach is, during the day, hotter than the water and your feet get burned when you walk on a sandy beach on a sunny day

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(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain

Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN => Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

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3 years ago

A student standardizes a solution of aqueous NaOH against a measured mass of solid potassium hydrogen phthalate. She then uses t

wlad13 [49]

Answer:

(D) Neither I nor II

Explanation:

The reagent potassium hydrogen phthalate is found in pure form and it is not partially hydrated .

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Hence option D ) is right choice .

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3 years ago

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3 years ago

Why is there so little evidence of the Period of Heavy Bombardment on Earth?

OverLord2011 [107]

C. Weathering, plate movements and volcanoes destroyed many of

the craters

Explanation:

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The period of heavy bombardment of the earth resulted in the creation of craters and other impact features on the earth surface.
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3 years ago

Read 2 more answers

A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill

LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

$BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)$

$Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)$

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

$\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%$

This means in 10.0 g, we have a total of:

$m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g$ of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

$\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%$

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

if this number is equal to 6.595 g, we have a pure sample of barium chloride;
if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.

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3 years ago