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natka813 [3]
3 years ago
6

a) Calculate the mass of Li formed by electrolysis of molten LiCl by a current of 8.2 104 A flowing for a period of 14 hr. Assum

e the electrolytic cell is 70. percent efficient. (b) What is the energy requirement for this electrolysis per mole of Li formed if the applied emf is +8.4 V? answer in kWh/mol
Chemistry
1 answer:
Sonja [21]3 years ago
8 0

a) Answer:

= 210,000 gram or 210 Kg  

Explanation:

14 hr is equivalent to;

= 14 × 3600 s

But; 

8.2x10^4 A = 8.2x10^4 Coulomb /second = 8.2x10^4 C/s  

1 Faraday = 96485C  

Molar mass of Li: 6.941 g/mol  

Therefore;

{(8.2x10^4 C/s)×(14×3600s)×(6.941 g/mol)/(96485C/mol)}×70%  

= 2.1x10^5 gram  or 210 kg

b.  Answer;

= 0.23 kWh/mol

Explanation and solution;

Energy per mole is given by;

(96485C/mol) × (8.4V) = 8.10x10^5 (J/mol)  

= 8.10x10^5 (Ws/mol)  

Divide by 3600s/h to get:  

= 8.10x10^5 (Ws/mol)

= 225 Wh/mol

= 0.23 kWh/mol

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Hydrochloric acid reacts faster with powdered zinc than with an equal mass of zinc strips because the greater the surface area o
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increases the frequency of particle collisions

Explanation:

One factor upon which the rate of reaction depends is the surface area of reactants.

According to the collision theory, reactions occur when reactant particles having the required (activation) energy collide with each other, this collision is inelastic. However, collision of particles having energies less than the activation energy results in elastic collisions and no chemical reaction.

The more the exposed surface area of reactants, the greater the number of particles that come into contact with each other and the more the chances of frequent effective collisions that lead to reaction.

Thus, powdered zinc reacts faster with hydrochloric acid than zinc strips

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3 years ago
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
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Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

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Therefore, order w.r.t C = 1

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<h3>Sulfuric acid</h3>

With the chemical formula H2SO4, sulfuric acid, also known as sulphuric acid or oil of vitriol, is a mineral acid made up of the elements hydrogen, oxygen, and sulfur. It is a viscous liquid that is miscible with water and is colorless, odorless, and viscous.

Since pure sulfuric acid has a significant affinity for water vapor, it does not naturally occur on Earth; as a result, it is hygroscopic and rapidly collects water vapor from the atmosphere. Due to its potent dehydrating and oxidizing qualities, concentrated sulfuric acid is extremely corrosive to various materials, including rocks and metals. One significant exception is phosphorus pentoxide, which dehydrates sulfuric acid to sulfur trioxide instead of being dehydrated by sulfuric acid.

Learn more about Sulfuric acid here:

brainly.com/question/1107054

#SPJ4

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