Answer:
x = -6, or x = 7 is the ONLY correct solution of the given equation ![x^{2} + x - 30 = 12.](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2030%20%3D%2012.)
Step-by-step explanation:
Here, the given expression is ![x^{2} + x - 30 = 12.](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2030%20%3D%2012.)
or the standard form of the above expression is ![x^{2} + x - 30 - 12 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2030%20-%20%2012%20%3D%200)
or, ![x^{2} + x - 42 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2042%20%3D%200)
Now, if the equation is of the form![ax^{2} + bx + c = 0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%20%2B%20bx%20%2B%20c%20%3D%200)
Then, b = SUM OF THE ROOTS
and c = PRODUCT OF THE ROOTS
Similarly, in the above expression:
b = 1 = Sum of roots
and c = -42 = Product of the roots.
Here, for x = -6, or x = 7:
Sum of Roots = -6 + 7 = 1
Product of roots = (-6)(7) = -42
Hence, x = -6, or x = 7 is the ONLY correct solution of the given equation.
How many times did glenda either make less than 10 free throws or more than 26 free throws o/4,6,9,9 1/1,1,2,4,5,9 3/0,0,2;3,2,2
gayaneshka [121]
Answer:
12 throws
Step-by-step explanation:
Each time Glenda practiced her free throws, she recorded the
number of made baskets in a stem-and-leaf plot.
![\left|\begin{array}{c|ccccccccc}Stem&Leaves&\\------&--&--&--&--&--&--&---\\0&4&6&9&9\\1&1&1&2&4&5&9\\2&0&0&4&5&6&9\\3&0&0&2&3&2&2&7\end{array}\right|](https://tex.z-dn.net/?f=%5Cleft%7C%5Cbegin%7Barray%7D%7Bc%7Cccccccccc%7DStem%26Leaves%26%5C%5C------%26--%26--%26--%26--%26--%26--%26---%5C%5C0%264%266%269%269%5C%5C1%261%261%262%264%265%269%5C%5C2%260%260%264%265%266%269%5C%5C3%260%260%262%263%262%262%267%5Cend%7Barray%7D%5Cright%7C)
Number of Times she made less than 10 free throws =4
Number of Times she made more than 26 free throws =8
Total=4+8=12
She made 12 throws which were either less than 10 or more than 26.
You would start by saying his budget is $80 so you start with 80= he pays an initial fee of $59.50 every month plus $5 per gigabyte so you would set it up like
80=59.50+5x
X being how many gigabytes he uses then you solve 80-59.50 is 20.5 divided by 5 gives you 4.1 but you round down cause you don’t want to pass the limit so therefor the most gigabytes he can use is 4
I can’t see it I just see black