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kati45 [8]
3 years ago
12

What shape do we expect for a graph showing the position of a motorcycle versus time if the motorcycle is speeding up with a con

stant acceleration?
Mathematics
1 answer:
posledela3 years ago
6 0
The position versus time graph is parabolic is <span>shape do we expect for a graph showing the position of a motorcycle versus time if the motorcycle is speeding up with a constant acceleration. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>
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Solve for x in the parallelogram.<br><br><br><br> The solution is x= <br> units.
natka813 [3]

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2 years ago
Trigonometry, can anybody help??
WINSTONCH [101]

Answer:

angle B: 39

AC: 7.288

AB: 11.58

(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)

Step-by-step explanation:

To solve this we will use SOH, CAH, TOA

we have the angle and the one opposite to it which means we can use either SOH or TOA

let's use TOA

tan(51)=(9/x)

x= 7.288

We can now use pahtagaryous theroem to solve for the hyptonouse

we have

9²+7.288²=C²

C=11.58

Finally, to find angle B we will recall that the angles of a triangle must add to 180.

51+90+a=180

a=39

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3 years ago
Please find the missing number for the surface area. I will mark brainiest if correct. 2.
Paha777 [63]

It is 18 because it is a square so all the sides have to be the same so that would make it 18

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3 years ago
If √(0.09×0.09×x) = 0.09 × 0.09×√z, then the value of x/y is____.​
OLEGan [10]

Given that-

√(0.09×0.09×x) = 0.09×0.09×√z

On squaring both sides then

⇛[√(0.09×0.09×x) ]² = (0.09×0.09×√z)²

⇛ 0.09×0.09×x= (0.09)²×(0.09)²×(√z)²

⇛ (0.09)² × x = (0.09)²×(0.09)²×z

⇛ (0.09)² × x/z = (0.09)²×(0.09)²

⇛x/z = (0.09)²×(0.09)²/(0.09)²

⇛x/z = (0.09)²

⇛x/z = 0.09×0.09

⇛x/z = 0.0081

<u>Answer</u><u>:</u><u>-</u> Hence the value of x/z will be 0.0081 r respectively.

3 0
3 years ago
What is the measure of arc AC
Bond [772]
The answer is d.
150 180-30= 150
TADA
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