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nexus9112 [7]
4 years ago
9

The probability that a can of paint contains contamination is 3.23%, and the probability of a mixing error is 2.4%. The probabil

ity of both is 1.03%. What is the probability that a randomly selected can has contamination or a mixing error?
Mathematics
1 answer:
stich3 [128]4 years ago
3 0

Answer:

4.6%.

Step-by-step explanation:

The probability that a can of paint contains contamination(C) is 3.23%

P(C)=3.23%

The probability of a mixing(M) error is 2.4%.

P(M)=2.4%

The probability of both is 1.03%.

P(C \cap M)=1.03\%

We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. P(C \cup M)

In probability theory:

P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%

The probability that a randomly selected can has contamination or a mixing error is 4.6%.

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