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aniked [119]
3 years ago
13

The sum of two consecutive integers is 4,031. What are the integers?

Mathematics
2 answers:
Sati [7]3 years ago
8 0
They are 2015 and 2016.

divide 4031 by 2, and get rid of the decimal:
You will get 2015.
2015+2015 = 4030
2015+2016=4031
Gennadij [26K]3 years ago
8 0

First represent your 2 consecutive integers as follows.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

Since their sum is 4,031, our equation reads x + (x + 1) = 4,031.

Simplifying on the left side, we get 2x + 1 = 4,031.

Now subtract 1 from both sides to get 2x = 4,030.

Now divide both sides by 2 to find that x = 2,015.

If <em>x</em> ix 2,015, then <em>x + 1</em> will be 2,015 + 1 or 2,016.

So our 2 consecutive integers are 2,015 and 2,016.

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