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3 years ago

9

PLEASE!!!I NEED HELP!!!!!!!

2 answers:

damaskus [11]3 years ago

7 0

Which value is equivalent to: (Picture Above?)
C.12/5
Hope this helps!

den301095 [7]3 years ago

3 0

It is c 12/5

hope it helps

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Help... need it right now ;-;

zalisa [80]

Answer:

1

Step-by-step explanation:

|3 + 2 - 6| = |5 - 6| = |-1| = 1

3 0

3 years ago

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What is 0.0592 in scientific notation

DiKsa [7]

Answer:

5.92 times 10 to the 2nd power.

Step-by-step explanation:

So funny I just finished my unit on scientific notation! So what you do is you count the distance from the first non-zero number (in this case, it would be after 5), and count how many places there are until the decimal point. I hope this helped! :D

7 0

3 years ago

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Please help with #12

ExtremeBDS [4]

Answer:

a. 1 1/8 b. 8/9

Step-by-step explanation:

You can set this up as a proportion to solve. For part a. we know that 2/3 of the road is 3/4 mile long. 2/3 + 1/3 = the whole road, so we need how many miles of the road is 1/3 its length. Set up the proportion like this:

$\frac{\frac{2}{3} }{\frac{3}{4} } =\frac{\frac{1}{3} }{x}$

Cross multiplying gives you:

$\frac{2}{3}x=\frac{1}{3}*\frac{3}{4}$

The 3's on the right cancel out nicely, leaving you with

$\frac{2}{3}x=\frac{1}{4}$

To solve for x, multiply both sides by 3/2:

$\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2}$ gives you

$x=\frac{3}{8}$

That means that the road is still missing 3/8 of a mile til it's finished. The length of the road is found by adding the 3/4 to the 3/8:

$\frac{3}{4}+\frac{3}{8}=\frac{6}{8}+\frac{3}{8}=\frac{9}{8}$

So the road is a total of 1 1/8 miles long.

For b. we need to find out how much of 1 1/8 is 1 mile:

1 mile = x * 9/8 and

x = 8/9. When 1 mile of the road is completed, that is 8/9 of the total length of the road completed.

8 0

3 years ago

From first principles, find the indicated derivatives

LenaWriter [7]

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

6 0

2 years ago

What’s the commutative property of addition ?

spin [16.1K]

Answer:

Its when you just swthc your thingy

Step-by-step explanation:

2+4=6

turns into

4+2=6

6 0

2 years ago

Read 2 more answers