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sertanlavr [38]
4 years ago
12

A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to custome

r requirements. Round your answers to the nearest integer. a. How many different samples are possible? b. How many samples of 3 contain exactly one nonconforming chip? c. How many samples of 3 contain at least one nonconforming chip?
Mathematics
1 answer:
Hatshy [7]4 years ago
6 0

Answer:

A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.

a) Number of different samples = 20C3 =  \frac{20!}{3!(17!)} =1140

b) 2 good and one bad chip

Number of samples = 10C2 * 10C1 = 45 * 10 =450

c) 2 good 1 bad + 1 good 2 bad + 3 bad

Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3

= 450+450+120=1020

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1.50 x 9= 13.50 the price of rides times the number of rides
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3 years ago
Solve for x: 4 − (x + 2) < −3(x + 4) 90 points!!!!!
slava [35]

Hello :)

First, solve each side before we solve the inequality

4 − (x + 2)                                                                  

−3x − 12                                                                              

− (x+2)

4 − x − 2

*group the like terms*

− x + 4 − 2

− x + 2

−3(x + 4)

−3(x + 4)

3x − 12

− x + 2 < 3x − 12

subtract 2 from both sides

− x + 2 < −3x − 12

      -2             -2

−x < − 3x − 14

add 3x to both sides

−x < − 3x − 14

+3x   +3x

2x < − 14

divide both sides by 2

\frac{2x}{2}<\frac{-14}{2}

<h2>x < − 7</h2>

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3 years ago
Is 4.15 larger, smaller or equal to 415 tenths.
igor_vitrenko [27]

Answer:

smaller

Step-by-step explanation:

7 0
3 years ago
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Determine if each ordered pair is a part of the solution set of the linear inequality. Select Yes or No.
lana [24]

Answer:

yes

Step-by-step explanation:

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3 years ago
Una empresa exportadora de frutas vende dos variedades de frambuesas: estándar y de lujo. Una caja de freses estándar se vende e
aksik [14]

Answer:

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

Step-by-step explanation:

Representemos el número de cajas como

A = caja estándar de frambuesas

B = caja de lujo de frambuesas

Caja estándar de frambuesas = $ 7 Caja de lujo de frambuesas = 10.

A + B = 135 ......... Ecuación 1

B = 135 - A

7A + 10B = 1100 ........... Ecuación 2

Sustituir

135 - A para B en la ecuación 2

7A + 10 (135 - A) = 1100

7A + 1350 -10A = 1100

7A - 10A = 1100-1350

-3A = - 250

A = 250/3

A = 83.33 cajas

Sustituye 83.33 por A en la ecuación 1

A + B = 135

83,33 + B = 135

B = 135 - 83.33 = 51.67 cajas

Por lo tanto, vendió,

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

6 0
3 years ago
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