Answer:
The base of triangle is
and the height of triangle is 
Step-by-step explanation:
Given:
A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.
Now, to find the base and height of the triangle.
The base of triangle = 
The height of triangle = 
The area of triangle = 
Now, we put the formula of area to solve:



<em>Multiplying both sides by 16 we get:</em>
<em />
<em />
<em>Dividing both sides by 3 we get:</em>
<em />
<em />
<em>Using square root on both sides we get:</em>


Now, by substituting the value of
to get the base and height:

<em>So, the base of triangle = </em>
<em />

<em>Thus, the height of triangle = </em>
<em />
Therefore, the base of triangle is
and the height of triangle is 
I will do Point A carefully, The others I will indicate. Start with the Given Point A. Then do the translations
A(-1,2) Original Point
Reflection: about x axis:x stays the same; y becomes -y:Result(-1,-2)
T<-3,4>: x goes three left, y goes 4 up (-1 - 3, -2 + 4): Result(-4,2)
R90 CCW: Point (x,y) becomes (-y , x ) So (-4,2) becomes(-2, - 4): Result (-2, - 4)
B(4,2) Original Point
- Reflection: (4, - 2)
- T< (-3,4): (4-3,-2 + 4): (1 , 2)
- R90 CCW: (-y,x) = (-2 , 1)
C(4, -5) Original Point
- Reflection (4,5)
- T<-3,4): (4 - 3, 5 + 4): (1,9)
- R90, CCW (-9 , 1)
D(-1 , -5) Original Point
- Reflection (-1,5)
- T(<-3,4): (-1 - 3, 5 + 4): (-4,9)
- R90, CCW ( - 9, - 4)
Note: CCW means Counter Clockwise
The graph on the left is the same one you have been given.
The graph on the right is the same figure after all the transformations
Answer:
im pretty sure the distance is across the y and x axis
Step-by-step explanation:
Answer:
16.5 square units
Step-by-step explanation:
You are expected to integrate the function between x=1 and x=4:

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<em>Additional comment</em>
If you're aware that the area inside a (symmetrical) parabola is 2/3 of the area of the enclosing rectangle, you can compute the desired area as follows.
The parabolic curve is 4-1 = 3 units wide between x=1 and x=4. It extends upward 2.25 units from y=4 to y=6.25, so the enclosing rectangle is 3×2.25 = 6.75 square units. 2/3 of that area is (2/3)(6.75) = 4.5 square units.
This region sits on top of a rectangle 3 units wide and 4 units high, so the total area under the parabolic curve is ...
area = 4.5 +3×4 = 16.5 . . . square units