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julsineya [31]
3 years ago
8

A researcher randomly assigned N = 16 rodents to experience one of four levels of shock (n = 4 per group) following the illumina

tion of a visual cue. If SSBG = 24 and SSE = 48, then what was the decision at a .05 level of significance for a one-way between-subjects ANOVA?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

The hypothesis should be retained

Step-by-step explanation:

We are given:

N= 16

n = 4

SS_B_G = 24

SS_E = 48

Level of significance, a = 0.05

From the given data, our ANOVA table will be:

----Source: Between---- Residual---

------DF:n-1=> 4-1=3------N-n=>16-4=12

------SS: SS_B_G = 24---- SS_E =48

----MS: MS_B_G = 8----MS_E=48/12=4

Note: proper ANOVA table is attached

The statistic will be written as:

TS = \frac{MS_B_G}{MS_E} ~ F_n_-_1, _N_-_n

T = 8/4 = 2

Therefore

F_n_-_1, _N_-_n, _a

=> F_3,_1_2,_ 0_._0_0_5 = 3.490

The hypothesis should be retained, because we no know that the statistic is in the acceptance area.

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Answer:

a) AUC = {2,4,6,8,10}

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