Question

A researcher randomly assigned N = 16 rodents to experience one of four levels of shock (n = 4 per group) following the illumination of a visual cue. If SSBG = 24 and SSE = 48, then what was the decision at a .05 level of significance for a one-way between-subjects ANOVA?

Answer 1

Answer:

The hypothesis should be retained

Step-by-step explanation:

We are given:

N= 16

n = 4

$SS_B_G = 24$

$SS_E = 48$

Level of significance, a = 0.05

From the given data, our ANOVA table will be:

$----Source: Between---- Residual---$

$------DF:n-1=> 4-1=3------N-n=>16-4=12$

$------SS: SS_B_G = 24---- SS_E =48$

$----MS: MS_B_G = 8----MS_E=48/12=4$

Note: proper ANOVA table is attached

The statistic will be written as:

$TS = \frac{MS_B_G}{MS_E} ~ F_n_-_1, _N_-_n$

T = 8/4 = 2

Therefore

$F_n_-_1, _N_-_n, _a$

$=> F_3,_1_2,_ 0_._0_0_5 = 3.490$

The hypothesis should be retained, because we no know that the statistic is in the acceptance area.