Tactical adoption is a quick-sighted technique, deploying cloud offerings incrementally, resulting in apps and offerings which might be patched collectively to create give-up-to-cease enterprise processes.
Cloud adoption is a method utilized by organizations to enhance the scalability of net-based database capabilities at the same time as lowering fee and dangers. To achieve this, organizations interact within the exercise of cloud computing or the use of faraway servers hosted at the net to save, control, and procedure essential records.
The primary benefit of cloud adoption is that it gives scalable organization IT with velocity. Speed may be understood as performance and is a pre-requisite for gaining competitive gain. The cloud offers the required speed for a corporation to release new products quickly and advantage competitiveness in markets without problems.
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Answer:
775 units
Explanation:
By forecast,
June sales = 400 units
July sales = 700 units
if ending inventory equal to 125% of next month's sales
Then June's ending inventory = 125% × 700
= 875 units
May's ending inventory = 125% × 400
= 500 units
Opening inventory + production - sales = closing inventory
Using the formula above, where p = production
500 + p - 400 = 875
p = 875 - 100
p = 775
Production required for June is 775 units.
Answer:
Present Value= $15,874.25
Explanation:
Giving the following information:
Assume the real rate of interest is 3.00% and the inflation rate is 6.00%. What is the value today of receiving 14,488.00 in 13.00 years?
<u>This is a rare case where the interest rate is negative:</u>
Interest rate= 0.03 - 0.06= -0.03
Having said this, the present value is higher than the final value:
PV= FV/ (1+i)^n
PV= 14,488/ 0.97^3= $15,874.25
Answer:
Start keeping a budget
Explanation:
All of the financial guidance from experts won’t mean much if you don’t know where your money is going every month. Start tracking your spending and set up a budget using a simple spreadsheet or website apps.
Answer:
a) H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
b) t stat = -0.064
c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
Explanation:
<u>a) stating the null and alternative hypothesis</u>
H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
<u>b) performing the test </u>
critical value = -2.88
T stat = coefficient / std error
= -0.02 / 0.31 = -0.064
c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
