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stellarik [79]
3 years ago
10

Help please!

Chemistry
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

Correct answer - wheels

Explanation:

<u>Limiting reactant:</u>

The reactant that is used up first in the chemical reaction.i.e. the reactant that restricts the amount of product that can be produced.The unused product left in the reaction.

For example,

2H_{2}+O_{2}\rightarrow 2H_{2}O

The ratio of creating H_{2}O is

2molH_{2}:1molO_{2}:2molH_{2}O

If you had 8 moles of hydrogen and only 3 moles of oxygen ;you would have enough oxygen to produce 6 moles of water with 2 moles of hydrogen leftover.

From the given,

200 handle bars, 150 wheels,  250 pedals, and 75 seats.

For tricycle making, each one required one seat, handle,two pedals and three wheels.

Hence, wheels are first consumed.

Therefore,  wheels are limiting reactant.

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Based on the following information, Cl2(g) + 2 e- → 2 Cl-(aq) E° = + 1.36 V Mg2+(aq) + 2 e- → 2 Mg(s) E° = -2.37 V which of the
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Answer:

D) Mg(s)

Explanation:

We are given:

E^o_{(Cl_2/Cl^-)}= 1.36V\\E^o_{(Mg^{2+}/Mg)}=-2.37V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, chlorine will undergo reduction reaction will get reduced.  Magnesium will undergo oxidation reaction and will get oxidized.

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4 years ago
What is the pH of an aqueous solution of 1 M CH3COOH (pKa=4)
Mrac [35]

Answer:

pH = 2.

Explanation:

A weak acid is in equilibrium with its ions in a solution, so it must have an equilibrium constant (Ka). And, pKa = -logKa

Ka = 10^{-pKa}

Ka = 10⁻⁴

So, for CH₃COOH the equilibrium must be:

CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)

1 M                           0                0                Initial

-x                              +x              +x               Reacted

1-x                             x                x                 Equilibrium

And the equilibrium constant:

Ka = \frac{[H+]x[CH3COO-]}{[CH3COOH]}

10^{-4} = \frac{x^2}{1-x}

Supposing x << 1:

10⁻⁴ = x²

x = √10⁻⁴

x = 10⁻² M, so the supposing is correct.

So,

pH = -log[H⁺]

pH = -log10⁻²

pH = 2

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Answer:

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