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Elena L [17]
3 years ago
12

What are the chemical properties of kevlar

Chemistry
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

<h2>Kevlar has unique properties such as:</h2><h2><em>High tensile strength</em>, <em>high toughness</em>, and <em>chemical stability </em>at high temperatures<em> </em>in polyamides (polymer with repeating unit links by amide bonds.) </h2><h3>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3>

Δ What is Kelvar? Δ

~ Kevlar is a heat-resistant and strong synthetic fiber

~ Kevlar is widely used as a friction material in the automotive industry, and a combustion protection material in the aerospace industry. <em>~Looked that up!</em>

<h3>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3>

<em>Hope I helped!!!</em>

<em>GL :)</em>

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What is the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution?
RoseWind [281]

Answer: 0.4M

Explanation:

Given that,

Amount of moles of NaOH (n) = ?

Mass of NaOH in grams = 40.0g

For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g

NaOH = (23g + 16g + 1g)

= 40g/mol

Since, n = mass in grams / molar mass

n = 40.0g / 40.0g/mol

n = 1 mole

Volume of NaOH solution (v) = 2.5 L

Concentration of NaOH solution (c) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

c = 1 mole / 2.5 L

c = 0.4 mol/L (Concentration in mol/L is the same as Molarity, M)

Thus, the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution is 0.4 mol/L or 0.4M

7 0
3 years ago
How many grams of HCl(aq) are required to react completely with 1.25g of Zn(s) to form ZnCl2(aq) and H2
faltersainse [42]

1.39 g HCl

Explanation:

The balanced chemical equation for this reaction is given by

Zn(<em>s</em>) + 2HCl(<em>aq</em>) ---> ZnCl2(<em>aq</em>) + H2(<em>g</em>)

Convert the # of grams of Zn to moles:

1.25 g Zn × (1 mol Zn/65.38 g Zn) = 0.0191 mol Zn

Use the molar ratio to find the # of moles of HCl needed to react completely with the given amount of Zn:

0.0191 mol Zn × (2 mol HCl/1 mol Zn) = 0.0382 mol HCl

Convert this amount to grams:

0.0382 mol HCl × (36.458 g HCl/1 mol HCl) = 1.39 g HCl

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