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Viktor [21]
2 years ago
10

Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li

counterion, and lone pairs are not required in the products.
Chemistry
1 answer:
dem82 [27]2 years ago
4 0

Answer:

Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li counterion, and lone pairs are not required in the products and the question is hsown below:

Explanation:

The proton from water is abstracted by butyl carbanion and hydroxide ion is formed from water.

The reaction is shown below in the attachment.

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Consider the reaction below. If you start with 4.00 moles of C3H8 (propane) and 4.00 moles of O2 , how many moles of propane wou
fgiga [73]

Answer:

0.800 mol

Explanation:

We have the amounts of two reactants, so this is a limiting reactant problem.  

We know that we will need a balanced equation with moles of the compounds involved.  

Step 1. <em>Gather all the information</em> in one place.

            C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol:  4.00    4.00

===============

Step 2. Identify the <em>limiting reactant </em>

Calculate the <em>moles of CO₂</em> we can obtain from each reactant.  

<em>From C₃H₈:</em>

The molar ratio of CO₂: C₃H₈ is 3:1

Moles of CO₂ = 4.00 × 3/1

Moles of CO₂ = 12.0 mol CO₂

<em>From O₂</em>:

The molar ratio of CO₂: O₂ is 3:5.

Moles of CO₂ = 4.00 × ⅗

Moles of CO₂ = 2.40 mol CO₂

O₂ is the limiting reactant because it gives the smaller amount of CO₂.

==============

Step 3. Calculate the <em>moles of C₃H₈ consumed</em>.

The molar ratio of C₃H₈:O₂ is 1:5.

Moles of C₃H₈ = 4.00 × ⅕

Moles of C₃H₈ = 0.800 mol C₃H₈

7 0
3 years ago
Which of the following is not a type of fault?
bekas [8.4K]

normal is the answer


8 0
3 years ago
Determine the grams of Iron(III) chloride produced if 22.5 g Iron reacts with Chlorine gas. First, balance the chemical equation
TEA [102]
22.5 because it still stays the same
4 0
3 years ago
Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).
Artemon [7]

Answer:

5.9x10^-2 M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M

5 0
3 years ago
Oxygen and copper are examples of what?
taurus [48]
Two different elements
5 0
3 years ago
Read 2 more answers
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