Answer:
Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li counterion, and lone pairs are not required in the products and the question is hsown below:
Explanation:
The proton from water is abstracted by butyl carbanion and hydroxide ion is formed from water.
The reaction is shown below in the attachment.
Answer:
= 0.551J/(g°C)
Explanation:
Specific heat is the amount of heat to required to raise the temperature of 1 gram substance to 1° C
The formula
C = q / m × ΔT ______ (1)
where ,
C = specific heat
q = heat
m = mass
ΔT = change in temperature
mass of the stainless steel is m = 1.55g
heat of the stainless steel is q = 141 J
the change in temperature is ΔT = 178°C
substitute all the value in the equation (1)
Explanation:
Let us assume that the given data is as follows.
mass of barium acetate = 2.19 g
volume = 150 ml = 0.150 L (as 1 L = 1000 ml)
concentration of the aqueous solution = 0.10 M
Therefore, the reaction equation will be as follows.
Hence, moles of =
.......... (1)
As, No. of moles =
Hence, moles of will be calculated as follows.
No. of moles =
= (molar mass of
is 255.415 g/mol)
=
Moles of =
= 0.01715 mol
Hence, final molarity will be as follows.
Molarity =
=
= 0.114 M
Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.
