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Elena-2011 [213]
3 years ago
11

2Al + 3MnSO4 ↔ Al2(SO4)3 + Mn

Chemistry
1 answer:
Stells [14]3 years ago
5 0
In accordance with the Le Chatelier's Principle, when the concentration of the aluminum increases then the equilibrium would shift to the right. It will produce more products since there are more reactants available and also collision is more frequent.
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What was one idea Dalton taught about atoms
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The main points of Dalton's atomic theory, as it eventually developed, are: Elements are made of extremely small particles called atoms. Atoms of a given element are identical in size, mass and other properties; atoms of different elements differ in size, mass and other properties.

4 0
3 years ago
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What is the velocity of a 500 kilgram elevator that has 4000 joules of energy?
nirvana33 [79]
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5 0
3 years ago
MARK BRAINLIEST AND 14 POINTS
LekaFEV [45]

Answer:

She could prove that it is a combination of substances by looking for a change in color, or the formation of bubbles. She could also try to pull the combination apart by physical means alone.

Explanation:

4 0
3 years ago
Read 2 more answers
How many moles of gold are there in 3.73 x 10^24 atoms of gold?
BARSIC [14]

Answer:

6.2moles of Gold

Explanation:

To solve this problem, we are going to use the mole concept approach.

 Given that;

  Number of atoms of gold is 3.73 x 10²⁴ atoms

Now;

  In 1 mole of any substance, we have 6.02 x 10²³ atoms;

   So;

  If there  6.02 x 10²³ atoms in  1 mole of any substance;

                 3.73 x 10²⁴ atoms will contain  \frac{3.73 x 10^{24} }{6.02 x 10^{23} }    = 6.2moles of Gold

4 0
2 years ago
The enthalpy change for converting 1.00 mol of ice at -25.0 °c to water at 70.0 °c is __________ kj. the specific heats of ice
Margarita [4]
Answer is: 6,16 kJ.
1) changing  temperature of ice from -25°C to 0°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 2 J/g·°C · 25°C 
Q₁ = 900 J.
m(H₂O) = 1mol · 18 g/mol = 18 g.
C - <span>specific heat of ice.
</span>2) changing temperature of water from 0°C to 70°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 4,18 J/g·°C · 70°C 
Q₁ = 5266,8 J.
C - specific heat of water.
Q = Q₁ + Q₂ = 900 J + 5266,8 J
Q = 6166,8 J = 6,16 kJ.

8 0
2 years ago
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