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madam [21]
3 years ago
7

Consider the function represented by the equation y – x – 4 = 0. What is the equation written in function notation, with x as th

e independent variable?
Mathematics
1 answer:
yarga [219]3 years ago
4 0
The equation in function notation with x as the independent variable is y = x + 4. In this type of equation needs to put dependent variable at left side and independent variable at right side.
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I'm going to try this one more time...
irina [24]

Answer and Step-by-step explanation:

<u>C and D  is the answer.</u>

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A is incorrect because the mass of our sun hasn't made it to collapse, and it still has some billions of years before the mass increases.

B is incorrect because the hydrogen needs to be depleted in order for the sun/star to start the nuclear process.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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3 years ago
How do I multiply 7.86 by 4.6
astraxan [27]
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3 years ago
A runner increases his velocity from 0 m/s to 20 m/s in 2.0s. What was his average acceleration?
xenn [34]

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7 0
3 years ago
WILL GIVE BRAINLIEST ANSWER!!
Natasha2012 [34]
Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}&#10;\\\\\\&#10;\boxed{b=\cfrac{200}{tan(16.38^o)}-a}&#10;\\\\\\&#10;tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}

make sure your calculator is in Degree mode.

4 0
3 years ago
Read 2 more answers
F(x)=x²+3x+2 is shifted 2 units right. The result is g(x). What is g(x)?
Nikolay [14]

The answer to this question is option D

8 0
2 years ago
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