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gladu [14]
3 years ago
10

Solve for a 1/4a+1/3=1/3a+5/4

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

1/4a+1/3=1/3a+5/4

1/4a-1/3a+1/3=1/3a-1/3a+5/4

1/4a-1/3a+1/3=5/4

1/4a-1/3a+1/3-1/3=5/4-1/3

1/4a-1/3a=5/4-1/3

Figure the common denominator for 1/4a,1/3a, 5/4 and -1/3 which is 12

Multiply by 3 for 1/4a. (1)(3)/4(3a)=3/12a

Multiply by 4 for 1/3a. (1)(4)(3)(4a)=4/12a

Multiply by 3 for 5/4. (5)(3)/4(3)=15/12

Multiply by 4 for -1/3. (-1)(4)(3)(4)=-4/12

3/12a-4/12a=15/12-4/12

-1/12a=11/12

Multiply by -12/1 for -1/12a and 11/12

-1/12(-12/1)a=11/12(-12/1)

Cross out 12 and -12 , divide by 12 and then becomes -11.

Cross out -12 and -12 , divide by 12 and then becomes 1.

Cross out -1 and 1, divide by 1 and then becomes 1.

1*1*a=-11

a=-11

Answer: a=-11

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Take the horse to overtake the
S_A_V [24]

Answer:

  • 120 km/h

Step-by-step explanation:

  • Speed in one direction = 40 km/h
  • Speed on return = x
  • Average speed = 60 km/h

Let the distance be d

<u>Average speed </u>

  • 2d/(d/40 + d/x) = 60
  • d/40 + d/x = 2d/60
  • 1/40 + 1/x = 1/30
  • 1/x = 1/30 - 1/40
  • 1/x = (4-3)/120
  • 1/x = 1/120
  • x = 120 km/h

6 0
3 years ago
10 - 2x, when x = 3<br>​
Nesterboy [21]

Answer:

4

Step-by-step explanation:

Plug in 3 as x in the expression:

10 - 2x

10 - 2(3)

10 - 6

= 4

4 0
3 years ago
Read 2 more answers
may wants to travel to the wedding a horse-drawn carriage. the horse trots at a speed of 15 km/h and Mary is getting dressed at
zepelin [54]
20min. 1h = 60min
15÷5=3
60÷3=20min
4 0
3 years ago
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a
Debora [2.8K]
If 3, 6, 9, 12, 15, and 18 are multiples of 3 between 1 and 20, and 5, 10, 15 and 20 are multiples of 5 between 1 and 20, then you add the amount of multiples together to get 10.

10 over 20 as a fraction can be simplified to 1 over 2 which is 50%.

This means that there is a 50% chance of drawing out a multiple of 3 or 5.

I hope this helps
7 0
3 years ago
The solution to a system of equations is (6-3). Choose two equations that might make up the system. Y= -3x+6 Y=2x-9 y=-5x+27 y=2
MakcuM [25]

Answer:  C) y = -5x + 27     and       D) y = 2x - 15

<u>Step-by-step explanation:</u>

Substitute x = 6 and y = -3 into each of the given equations to see which result in a TRUE statement.

A) y = -3x + 6

  -3 = -3(6) + 6

  -3 = -18 + 6

  -3 = -12     FALSE

B) y = 2x - 9

  -3 = 2(6) - 9

   -3 = 12 - 9

   -3 = 3     FALSE

C) y = -5x + 27

  -3 = -5(6) + 27

  -3 = -30 + 27

  -3 = -3    TRUE!

D) y = 2x - 15

  -3 = 2(6) - 15

  -3 = 12 - 15

  -3 = -3    TRUE!

E) y = -4x + 27

  -3 = -4(6) + 27

  -3 = -24 + 27

  -3 = 3   FALSE

6 0
3 years ago
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