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enyata [817]
3 years ago
7

4. A bike rental company rented out 8 bikes in its first month. The company increased the number of bikes it rented each month b

y 2%. What was the approximate total number of bikes the company will rent out for the first 9 months?
50

59

68

78
Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0
This is a geometric sequence:

First month: 8
Second month: 8 * 1.02
Third month: 8*1.02^2
Fourth month 8* 1.02^3
...
nth month: 8 * 1.02 ^(n-1)

Sum of the first 9 terms (months) = a[1 -r^n] / (1 - r) = 8* [1 - 1.02^9] / (1 - 1.02) = 78.04

Answer: approximately 78 bikes.
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If you know the diameter of the circle, multiply the diameter by PI

 if you know the radius of the circle multiply the radius by 2 then multiply by PI

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3 years ago
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Juan is making birdhouses
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4 years ago
Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

a.

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

b)

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20log_%7Ba%7D%28%20%5Csqrt%7Ba%7D%20%5Csqrt%7Ba%7D%20%5Csqrt%7Ba%7D%29" id="TexFormula1" titl
ad-work [718]

Step-by-step explanation:

log_{a}(a)  ^{x}   = x

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3 years ago
The perimeter of Dawna's new flat screen television is 112 inches. The ratio of its length to width is 4:3. Wire and solve an al
Dmitry_Shevchenko [17]
Hey there,
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Width = 3x
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x = 112 inches / 14
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 Hope this helps :))

<em>~Top♥</em>
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3 years ago
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