Do you mean an extraneous solution? I will tell you what I think. To tell if a solution is extraneous you need to go back to the original problem and check if there actually is a solution or if the solution is actually right. If not then it is extraneous.
Answer:
add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract
complex numbers by adding their real and imaginary parts:-
(a + bi)+(c + di)=(a + c)+(b + d)i,
(a + bi) − (c + di)=(a − c)+(b − d)i.
We can multiply complex numbers by expanding the brackets in the usual fashion and using i
2 = −1,
(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,
and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So
a + bi
c + di = a + bi
c + di ×
c − di
c − di =
µac + bd
c2 + d2
¶
+
µbc − ad
c2 + d2
¶
i.
The number c−di which we just used, as relating to c+di, has a spec
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A, sub in a random number as x in all equations and solve, eg- x= 3
2-3= -1
3-2=1
-2 +3= 1
3-2=1
Answer:
A
Step-by-step explanation:
The dilation with the center of dilation at the origin and scale factor of 4 has the rule
(x,y)→(4x,4y).
Thus,
- A(-1,3)→A'(-4,12)
- B(2,1)→B'(8,4)
- C(-2,-1)→C'(-8,-4)
A'(-4,12) - option B
B'(8,4) - option C
C'(-8,-4) - option D
