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Vikentia [17]
3 years ago
7

What is 2(-9x-4y-7) simplified

Mathematics
1 answer:
Setler79 [48]3 years ago
4 0
-18x-8y-14 because you need to distribute the digits
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What is 500 Divided by 4039.905
Vsevolod [243]

Answer:

0.12376528

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Algebra 1:Write an algebraic expression for 91 more than the square of a number
Bumek [7]

Give the number a name.  You can call it anything.  I'll call it ' G '.

The square of the number is  G²  .

91 more than that is          G² + 91  .

3 0
4 years ago
Helppp im stuck :(<br> Hope you guys help me
andriy [413]

Answer:

y=-\dfrac{1}{2}x+2

Step-by-step explanation:

Define two points on the line:

  \textsf{let}\:(x_1,y_1)=(0,2)

  \textsf{let}\:(x_2,y_2)=(4,0)

Use the slope formula and the defined points to find the slope:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-2}{4-0}=-\dfrac{1}{2}

Substitute the found slope and one of the points into the point-slope form of a linear equation:

\implies y-y_1=m(x-x_1)

\implies y-2=-\dfrac{1}{2}(x-0)

Simplify:

\implies y-2=-\dfrac{1}{2}x

\implies y=-\dfrac{1}{2}x+2

6 0
2 years ago
Use a table of values to estimate the value of the limit. Confirm your result graphically by graphing the function with a graphi
il63 [147K]
Hello,

\lim_{x \to 0}\dfrac{ \sqrt{x+25}-5}{x}\\\\

=\lim_{x \to 0}\dfrac{(\sqrt{x+25}-5)*(\sqrt{x+25}+5)}{x*(\sqrt{x+25}+5)}\\\\

=\lim_{x \to 0}\dfrac{x+25-25)}{x*(\sqrt{x+25}+5)}\\\\


=\dfrac{1}{10}

















4 0
3 years ago
Find tan 0 if csc 0 = -√5/2 is in the third quadrant.<br> A. 1/2<br> B.-2<br> C.-1/2<br> D. 2
MakcuM [25]

Answer:

D. 2

Step-by-step explanation:

soh cah toa rule

sine equals opposite over hypotenuse,

cosine equals adjacent over hypotenuse, and

tangent equals opposite over adjacent

csc is 1/sin which is hypotenuse over opposite

if csc is -√5/2 then

hypotenuse is -√5

opposite is 2

3rd quadrant on a graph is bottom left

both x and y values are negative

hypotenuse means its a triangle

pythagorean theorem

a^2 + b^2 = c^2

a^2 + 2^2 = (-√5)^2

a^2 + 4 = 5

a = 1 = adjacent

tangent equals opposite over adjacent

tan is 2 / 1 which is 2

third quadrant means it's still positive

because tan is positive in quadrant 3

intmathcom

revisionmathscom

mathworldwolframcom

4 0
2 years ago
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