A 60-cm spring will stretch (in cm) one third the weight (in kg) attached to it. How long will the spring be if a 20-kg weight i
1 answer:
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The complete question in the attached figure
Part a)
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm
the answer part a) is
AB=6 cm
Part b)
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³
the answer part b) is
100 cm³
Part a)
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm
the answer part a) is
AB=6 cm
Part b)
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³
the answer part b) is
100 cm³
Answer:
Step-by-step explanation:
The given polynomial equation is
We perform the synthetic division as shown in the attachment by dividing by x-2.
This gives a remainder of 0 and a quotient of
This means the polynomial equation becomes:
We factor the quadratic term by splitting the middle term;
Collect common factors again:
The solution is:
