A trapezoid in a coordinate plane has vertices (-2,5), (-3,-2), (2,-2), and (1,5). What is the height of the trapezoid?
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Answer:
Step-by-step explanation:
Standard form of the equation:
y =
Directrix: y=4
Focus: (-3,2)
Points on the parabola (x,y):
(-5,2) (-3,3) (-1,2)
Distance from points to focus:
(-5,2) = (-3,2)
Answer choices: (x+3)^2+(y−3)^2, (x−2)2+(y+3)2, (x+3)2+(y−2)2
(-5+3)^2+(2-3)^2=5
(-5-2)^2+(2+3)^2=74
(-5+3)^2+(2-2)^2=4
(-1,2)