Answer:
Empirical formula: CH₂
Explanation:
We need to find the empirical formula of a compound that has carbon and hydrogen.
To find the empirical formula of any compound, if we have the mass or mass percent, we should follow 3 steps:
<u>1. Calculate the moles, dividing by the atomic weight.</u>
The atomic weight for carbon and hydrogen are 12 g/mol and 1 g/mol, so, doing the division we have:
C = 85.5 / 12 = 7.125
H = 14.3 / 1 = 14.3
<u>2. Determine the number of atoms of each element in the formula</u>
To do this, we just divide the previous moles by the lowest quantity we obtain. In this case, the carbon:
C = 7,125 / 7,125 = 1
H = 14,3 / 7,125 = 2
This means we have 1 atom of carbon and 2 atoms of hydrogen.
<u>3. Write the empirical formula with the previously obtained atoms</u>
Now that we obtained the atoms of each element, we just write the empirical formula with these numbers:
C₁H₂ but we can neglect the number one so:
<h2>
Empirical formula: CH₂</h2>
Hope this helps
Water is a polar molecule because of its shape
0.000005 is your answer. Hope this helps!!
Answer:
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
Explanation:
Sodium hydroxide (NaOH) is a <u>strong base</u> and hydrochloric acid (HCl) is a <u>strong acid</u>. That means that they are totally dissociated into ions in aqueous solution.
When a solution of NaOH is mixed with a solution of HCl, a neutralization reaction occurs, in which a salt (NaCl) and water (H₂O) are formed.
The <em>balanced molecular equation</em> for this reaction is:
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
Answer:
False
Explanation:
J. J. Thomson conducted an experiment which lead to the discovery of negatively charged particles only. He took a discharged tube and passed high voltage current through the gas and noticed that some particles from cathode is being emitted. They are fast moving particles and are deviated in the electrical and the magnetic field.
<u>J. J. Thomson did not conclude anything about the positive charge. Hence, the statement is false.</u>