1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ket [755]
2 years ago
7

Where can you change the atom/molecules used in the simulation? Which atoms/molecules are

Chemistry
1 answer:
aivan3 [116]2 years ago
7 0

Answer:

When two or more atoms are chemically joined together, this is called a molecule. In some cases, such as hydrogen and oxygen, the molecule is made entirely of the same atom, such as hydrogen gas (a molecule) is made entirely of two hydrogen atoms. Here, converting molecules to atoms is as simple as dividing by two.

Atoms can join together - they form bonds together - to make MOLECULES. For example, two atoms of hydrogen hook together to form a molecule of hydrogen

You might be interested in
HELP ASAP
sergejj [24]

D- A molecule

Explanation:

(Apex)

3 0
3 years ago
Determine el PH y el % de disociación de una solución de ácido débil, sabiendo que se disuelven 20 gramos del ácido (masa molar=
IceJOKER [234]

Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Donde la constante de equilibrio, Ka, es

Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]

Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

[H⁺] = [X⁻]

[HX] es:

20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M

Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

pH = -log[H⁺]

<h3>pH = 4.27</h3>

El porcentaje de disociacion es [X⁻] / [HX] inicial * 100

Reemplazando

5.35x10⁻⁵M / 0.1732M * 100

<h3>0.03%</h3>
5 0
3 years ago
Iron forms rust, expressed as Fe2O3.
Elina [12.6K]

Answer:

it's C. 159.70 g

Explanation:

hopefully that helps

3 0
3 years ago
Given the standard enthalpy changes for the following two reactions:
lawyer [7]

Answer:

ΔH° = -186.2 kJ

Explanation:

Hello,

This case in which the Hess method is applied to compute the required chemical reaction. Thus, we should arrange the given first two reactions as:

(1) it is changed as:

SnCl2(s) --> Sn(s) + Cl2(g)...... ΔH° = 325.1 kJ

That is why the enthalpy of reaction sign is inverted.

(2) remains the same:

Sn(s) + 2Cl2(g) --> SnCl4(l)......ΔH° = -511.3 kJ

Therefore, by adding them, we obtain the requested chemical reaction:

(3) SnCl2(s) + Cl2(g) --> SnCl4(l)

For which the enthalpy change is:

ΔH° = 325.1 kJ - 511.3 kJ

ΔH° = -186.2 kJ

Best regards.

7 0
3 years ago
Read 2 more answers
As the speed of a particle increases, does its associated wavelenght increase or decrease
Zina [86]

The de Broglie hypothesis proposed that all particles have wave-like properties, with the wavelength being inversely proportional to the velocity of the particle.


Therefore as the velocity (speed in this question) increases, the wavelength *decreases*.

7 0
3 years ago
Other questions:
  • What ia 45.76×0.25 please help
    11·2 answers
  • What is a synonym
    9·2 answers
  • Why would it be more difficult to inject the nucleus of uranium with a proton?
    6·1 answer
  • What diet do bearded dragons thrive on?
    10·2 answers
  • Genetic engineers must modify eukaryotic genes so that they can be expressed in bacterial host cells. The DNA from a eukaryotic
    9·1 answer
  • At 20 degrees Celsius, the density of air is 1.20 g/L. Nitrogen's density is 1.17 g/L. Oxygen's density is 1.33 g/L. Will balloo
    12·2 answers
  • Grams needed to prepare the solution
    14·1 answer
  • Can someone help with b and c ??! Real answers :) 50 POINTS ;)
    9·1 answer
  • A chemist must prepare 0.200 L of aqueous silver nitrate working solution. He'll do this by pouring out some aqueous silver nitr
    11·1 answer
  • Which change is chemical?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!