In the given reaction fluorine is reduced and chlorine is oxidized.
<h3>What is oxidation and reduction?</h3>
Oxidation is a process in which addition of oxygen or removal of hydrogen and electron takes place, while reduction is a process in which addition of hydrogen & electrons or removal of oxygen takes place.
Given chemical reaction is:
F₂ + 2HCl → Cl₂ + 2HF
- In the above reaction fluorine is reduced as it accepts an electron and increase in it its oxidation state takes from 0 to -1, which shows reduction.
- In the reaction chlorine is oxidized as it losses an electron and decrease in its oxidation state takes from -1 to 0, which shows oxidation.
- Oxidation half reaction is:
F₂ + 2e⁻ → 2F⁻
- Reduction half reaction is:
2Cl⁻ → Cl₂ + 2e⁻
Hence, fluorine is reduced and chlorine is oxidized in the given reaction.
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Answer : The concentration of 
ion is 0.0375 M.
Explanation :
The balanced equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
![K_{sp}=[Pb^{2+}][Cl^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2)
Now put all the given values in this expression, we get:
![2.40\times 10^{-4}=[Pb^{2+}]\times (0.0800)^2](https://tex.z-dn.net/?f=2.40%5Ctimes%2010%5E%7B-4%7D%3D%5BPb%5E%7B2%2B%7D%5D%5Ctimes%20%280.0800%29%5E2)
![[Pb^{2+}]=0.0375M](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%3D0.0375M)
Therefore, the concentration of ion is 0.0375 M.
Answer: 6.75 moles of 
can be produced from 13.5 moles Na
Explanation:
The balanced chemical equation for formation of from Na is:
According to stoichiometry :
4 moles of Na give = 2 moles of
Thus 13.5 moles of 
give =
of
Thus 6.75 moles of can be produced from 13.5 moles Na
