No more solute will dissolve at that temperature, the temperature would have to be increased in order for more solute to dissolve.
The color emitted be larger atoms is lower in energy then the light emitted by smaller atoms
The new concentrations of
and
are 0.25M and 19M
Calculation of number of moles of each component,
Molarity of
= number of moles/volume in lit = 0. 500 M
Number of moles = molarity of
× volume in lit = 0. 500 M× 0.025 L
Number of moles of
= 0.0125 mole
Molarity of
= number of moles/volume in lit = 0. 38 M
Number of moles = molarity of
× volume in lit = 0. 38 M× 0.025 L
Number of moles of
= 0.95 mole
Calculation of new concentration at volume 50 ml ( 0.05L)
Molarity of
= number of moles/volume in lit = 0.0125 mole/0.05L
Molarity of
= 0.25M
Molarity of
= number of moles/volume in lit = 0.95mole/0.05L
Molarity of
= 19 M
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Answer:
<u><em>Pentane </em></u>
Explanation:
since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it 
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