Answer:
- <u>The complement of spinning any number less than 3, is spinning a number equal to or greater than 3.</u>
Explanation:
The complement of a subset is the subset of elements that are not in the given subset.
You must know which numbers the spinner has.
Assuming the spinner has the numbers 1, 2, 3, 4, the complement of spinning any number less than 3, is spinning a number that is not less than 3.
Then, that is spinning a number that is equal to or greater than 3.
The numbers that are equal to or greater than four, for a spinner that has the numbers 1, 2, 3, and 4 are 3 and 4.
Thus, the complement of spinning any number less than 3 is spinning a three or a four.
Don't you have to multiply the Area's ?
(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>
<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>
<span>x = -2, 0, +2 so your answer is going to be e
</span>
Answer:
2/19
Step-by-step explanation:
i just took the test and no one helped me i got is wrong but when you go back to review it it tells you the answer hope im not too late
