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3 years ago

14

Jack crawled 4 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what

is the total distance the two children crawled

1 answer:

ella [17]3 years ago

4 0

Your answer would be 4.75 for your answer

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18/30 reduce into fraction

Firlakuza [10]

Answer:

35 - reduced

0.6 - decimal

8 0

3 years ago

Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$

5 0

2 years ago

Slope intercept! Please help! Will mark brainliest.

avanturin [10]

3) y = $-\frac{1}{2}$ x + 3

Slope-intercept form is y = mx + b when m is the slope and b is the y-intercept

b = 2 (line hits y-axis at 2)

m = $\frac{rise}{run} or\frac{change.in.y}{change.in.x}$ so $\frac{1}{2}$ and the line is negative, so $-\frac{1}{2}$

Write our equation by putting the parts together, and we get:

y = $-\frac{1}{2}$ x + 3

4) y = $-\frac{2}{3}$ x - 1.67

Point slope form is y - y1 = m (x - x1) when y1 is the y coordinate of the point, m is the slope, and x1 is the x coordinate of the point

y - y1 = m (x - x1)

Finding the slope (same as above) results in $-\frac{2}{3}$

<em>*aaaa I have to go, good luck, I do have the answer just no times to write out the steps, good luck and have a nice day!*</em>

3 0

3 years ago

Many insects migrate (travel) between their summer and winter homes. The desert locust migrates about 800 miles farther than the

Harman [31]

Answer:

Distance travelled by Monarch butterfly = 2000 miles

Distance travelled by desert locust = 2800

Distance travelled by pink-spotted hawk moth= 7800 miles

Step-by-step explanation:

Let the distance travelled by Monarch butterfly be "X" miles

Distance travelled by desert locust is equal to X + 800 miles

Distance travelled by pink-spotted hawk moth is equal to 4X -200 miles

The total distance travelled by the three is equal to 12600 miles

$X + X + 800 + 4X -200 = 12600\\6X = 12600 -600\\6X = 12000\\X = 2000$

Distance travelled by Monarch butterfly = 2000 miles

Distance travelled by desert locust = 2000 + 800 = 2800

Distance travelled by pink-spotted hawk moth = 4 * 2000 -200 = 7800 miles

6 0

3 years ago

Is the quotient 3.6÷9 greater or less than one

anastassius [24]

3 6/10÷ 9
36/10×1/9
36/90
.4<1

(Less than)

Hope this helps!

3 0

3 years ago