All categories

4 years ago

What is 25 percent of 148

Mathematics

1 answer:

valentina_108 [34]4 years ago

8 0

Answer: 37

Step-by-step explanation: To find 25% of 148, first write 25% as a decimal by moving the decimal point two places to the left to get .25 which is the decimal equivalent to 25%.

Next, the word "of" means multiply so we will need to multiply.

(.25) (148) = 37

Therefore, 37 is 25% of 148.

You might be interested in

I really need help. What would be the slope-intercept equation?

Naddik [55]

Answer:

y = -3.71x + 147.25

Step-by-step explanation:

8 0

3 years ago

In response to a survey question about the number of hours daily spent watching TV, the responses by the eight subjects who iden

Basile [38]

Answer:

a) $\bar X = \frac{2+2+1+3+1+0+4+1}{8}= 1.75$

b) The margin of error indicates we can be 95%confident that the sample mean falls within 0.89 of the population mean

Step-by-step explanation:

Part a

The best point of estimate for the population mean is the sample mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Since is an unbiased estimator $E(\bar X) = \mu$

Data given: 2 , 2 , 1 , 3 , 1 , 0 , 4 , 1

So for this case the sample mean would be:

$\bar X = \frac{2+2+1+3+1+0+4+1}{8}= 1.75$

Part b

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

$ME=t_{\alpha/2}\frac{s}{\sqrt{n}}$ (2)

And for this case we know that ME =0.89 with a confidence of 95%

So then the limits for our confidence level are:

$Lower= \bar X -ME= 1.75- 0.89=0.86$

$Upperr= \bar X +ME= 1.75+0.89=2.64$

So then the best answer for this case would be:

The margin of error indicates we can be 95%confident that the sample mean falls within 0.89 of the population mean

7 0

3 years ago

Daisy, the african elephant weighs 10,250 pounds. The daily feed intake for an elephant is approximately 1.5% of the animals bod

AlexFokin [52]

Answer: a) 154 kilograms

Step-by-step explanation:

Given : Daisy, the african elephant weighs 10,250 pounds.

The daily feed intake for an elephant is approximately 1.5% of the animals body weight.

1.5% can be written as 0.015.

Now, the amount of feed is to be feed to Daisy to meet her requirements will be :_

$0.015\times10250=153.75\approx154$

Hence, 154 kilograms of feed is to be feed to Daisy to meet her requirements.

4 0

3 years ago

Please Help!!!

Leni [432]

<h2>Answer : (2.67, 3.53)</h2><h2></h2>

Step to step explanation:

Confidence interval for mean, when population standard deviation is unknown:

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = sample mean

n= sample size

s= sample standard deviation

$t_{\alpha/2}$ = Critical t-value for n-1 degrees of freedom

We assume the family size is normal distributed.

Given, n= 31 , $\overline{x}=3.1$ , s= 1.42 ,

$\alpha=1-0.9=0.10$

Critical t value for $\alpha/2=0.05$ and degree of 30 freedom

$t_{\alpha/2}$ = 1.697 [By t-table]

The required confidence interval:

$3.1\pm ( 1.697)\dfrac{1.42}{\sqrt{31}}\\\\=3.1\pm0.4328\\\\=(3.1-0.4328,\ 3.1+0.4328)=(2.6672,\ 3.5328)\approx(2.67,\ 3.53)$

Hence, the 90% confidence interval for the estimate = (2.67, 3.53)

6 0

3 years ago

Find the sum or difference. 8 1/6 + 7 3/8

Lilit [14]

15 13/24 or in decimal form 15.5416

4 0

3 years ago

Read 2 more answers

What is 25 percent of 148​

What is 25 percent of 148