Answer:
(x+3)(4x−2) = 4x2+10x−6
(x+2)(x2−3x +4) = x3−x2−2x+8
Step-by-step explanation:
Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
I think it is D
Hope my answer help you?
Answer:
option c. Alternate interior angles
Answer:
P'Q' is equal in length to PQ.
Step-by-step explanation:
Before rotation
P(-5, 3)
Q(-1, 3)
we get the length
L = √((-1-(-5))²+(3-3)²) = √((-4)²+(0)²) = 4
After rotation
P'(3, 5)
Q'(3, 1)
we get the length
L' = √((3-3)²+(1-5)²) = √((0)²+(-4)²) = 4
we can say that L = L' = 4
P'Q' is equal in length to PQ.
