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bulgar [2K]
3 years ago
7

If y+ 18=45 what does y equal?

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0
What plus 18 equals 45?
Flauer [41]3 years ago
7 0
You would want to subtract 18 from 45. Your answer would be y=27.
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Write each expression as an equivalent expression with a single logarithm. Assume xx, yy, and zz are positive real
Debora [2.8K]

Answer:

\ln\frac{xy^2}{z^3}

Step-by-step explanation:

Data provided:

ln(x) + 2 ln(y) − 3 ln(z)

Now,

From the properties of log function,

ln(A) + ln(B) = ln(AB)

n × ln(x) = ln(xⁿ)

and,

ln(A) - ln(B) = \ln\frac{A}{B}

applying the properties in the given equation

we get

⇒  ln(x) + 2 ln(y)  − 3 ln(z)

or

⇒ ln(x) + ln(y²) - ln(z³)            (using n × ln(x) = ln(xⁿ))

or

⇒ ln(xy²) - ln(z³)                    (using ln(A) + ln(B) = ln(AB) )

or

⇒ \ln\frac{xy^2}{z^3}   (using ln(A) - ln(B) = \ln\frac{A}{B} )

8 0
4 years ago
SHOW ALL WORK<br> What is y
azamat

Answer:

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Step-by-step explanation:

3 0
3 years ago
)) What is 2.825 rounded to the nearest whole number?
Shalnov [3]

Answer:

2.83

Step-by-step explanation:

25 round off is equal to 30

so we can write 2.825 = 2.83 in form of 2 digits

83 round off to 80

2.83 is equal to 2.8

4 0
3 years ago
Hey! i’ll give brainliest help thanks
valkas [14]
The answer to this is A
4 0
3 years ago
Read 2 more answers
Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and
STALIN [3.7K]

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

P(A) = \frac{4}{52} = \frac{1}{13}

Probability of choosing a face card, considering the previous card was a king.

12 face cards out of 51. So

P(B|A) = \frac{12}{51}

What is the probability of choosing a king and then, without replacement, a face card?

P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181

0.0181 probability of choosing a king and then, without replacement, a face card.

5 0
3 years ago
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