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3 years ago

The Doritos are $4.50 on sale. There are 15 oz in a bag. So, how much is 1 oz Of Doritos?

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

Thirty cents
$.30
hope this helps

11Alexandr11 [23.1K]3 years ago

5 0

It would be .30 cents because 4.50 divided by 15 = .30

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Simplify 7.1x106 ______ 8.2 x 101

vekshin1

Answer:

7.1x106=752.6

8.2 x 101=828.2

3 0

2 years ago

2. a. The center for research in data science has a vacancy of 5 interns under a research attachment program. However, 20 studen

Yuliya22 [10]

Answer: 15504

Step-by-step explanation:

Given : The center for research in data science has a vacancy of 5 interns under a research attachment program.

Number of students applied = 20

The combination of n people taking r at a time is given by :-

$C(n,r)=\dfrac{n!}{r!(n-r)!}$

Since, all students fulfill the minimum CGPA criteria it means all 20 students are equally eligible.

Then , the number of ways to select a team of 5 interns from all 20 interns :-

$C(20,5)=\dfrac{20!}{5!(20-5)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15!}{5!15!}\\\\=15504$

Hence, the number of ways to select a team of 5 interns. =

7 0

3 years ago

4 (3×-1)=3+8×-11 2 (t+2)+5t=6t+11

babymother [125]

X= -1 t= 7

4(3x-1)=3+8x-11
12x-4=3+8x-11
12x-8x=4+3-11
4x= -4
\4. \4
x= -1

2t+4+5t=6t+11
2t-6t+5t=-4+11
1t=7
\1. \1
t=7

3 0

3 years ago

Nitrates are groundwater contaminants derived from fertilizer, septic tank seepage and other sewage. Nitrate poisoning is partic

o-na [289]

Answer:

a) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401$

And rounded up we have that n=2401

b) $n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22$

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

Part a

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior information about the population proportion we can use ase estimator $\hat p =0.5$ . And replacing into equation (b) the values from part a we got: