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Maru [420]
3 years ago
6

Heyo bros i need you're help here.........​

Mathematics
2 answers:
Anarel [89]3 years ago
6 0

Answer:

prime number number that are divisible by itself n 1

=10

tekilochka [14]3 years ago
5 0
Your answer is: 10

Very easy to solve, hope this helps!:)
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In your notebook, set up the following addition using a vertical format and find the sum of the given polynomials. 3x 2 + 2x - 5
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3x^2
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10x^2 + 2x - 9
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What the result of √[(-2a)^ 2]
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If you take the square root of a number squared number then they cancel each other out and the number stays the same i.e. √[(4)^2] would equal 4.

In this problem the square root and numbered squared cancel out to leave the problem as -2a.

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Maggie constructs a triangle with sides lengths 7 centimeters long and 10 centimeters long.
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2 cm

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Is −1.28 a rational number?
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2 years ago
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What is the product?
Stels [109]

Answer:

Option A is correct.

Step-by-step explanation:

We need to find the product of

\frac{(x^2-16)}{(2x+8)} * \frac{(x^3-2x^2+x)}{(x^2+3x-4)}

We know (a^2-b^2) = (a+b)(a-b)

so, (x^2-16) = (x)^2-(4)^2 = (x-4)(x+4)

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(x^3-2x^2+x) Taking x common from this term

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(x^2+3x-4) factorizing this term

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= (x-1)(x+4)

Now, Putting these simplified terms in the given equation:

\frac{(x-4)(x+4)}{2(x+4)}*\frac{x(x-1)(x-1)}{(x-1)(x+4)}

Now cancelling the same terms that are in numerator and denominator

=\frac{(x-4)}{2}*\frac{x(x-1)}{(x+4)}\\=\frac{(x-4)(x)(x-1)}{2(x+4)}\\=\frac{x(x-4)(x-1)}{2(x+4)}

So, Option A is correct.

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