All categories

3 years ago

Heyo bros i need you're help here.........

Mathematics

2 answers:

Anarel [89]3 years ago

6 0

Answer:

prime number number that are divisible by itself n 1

=10

tekilochka [14]3 years ago

5 0

Your answer is: 10

Very easy to solve, hope this helps!:)

You might be interested in

Can someone PLEASE help me with this question, I've been having trouble for half a hour. Thank you!

ioda

The answer is D 6,804 square inches
the surface area of one net is 1,056
you multiply it by the number of packages and you get 6,804

5 0

3 years ago

Read 2 more answers

Rewrite the equation in standard form by expanding it. y= 3 (x+2)^2 - 4

morpeh [17]

Answer:

y = 3x^2 + 12x + 8

Step-by-step explanation:

To rewrite in standard from by expanding the equation using the distributive property.

y= 3 (x+2)^2 - 4

y = 3(x^2 + 4x + 4) - 4

y = 3x^2 + 12x + 12 - 4

y = 3x^2 + 12x + 8

4 0

3 years ago

P=2L +2W;P=32,W=7 25 16 12.5 9

Marianna [84]

Answer:

L = 9

Step-by-step explanation:

Assuming you are trying to find L

P = 2L + 2W

P = 32

32 = 2L + 2W

W = 7

32 = 2L + (2 × 7)

32 = 2L + 14

2L = 32 - 14

2L = 18

L = 9

5 0

3 years ago

A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po

Mariana [72]

Answer:

The work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

Step-by-step explanation:

The work is defined by:

$W=\int dFdx$ (1)

The force here will be the product between the volume and the kerosene weighing, so we have :

$dF=\pi R^{2}dy*50$

This force will be in-lbs.

Where R is the radius (3 feet)

Then using (1), we have:

$W=\int \pi R^{2}dy*50(8-y)$

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

$W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)$

$W=450\pi \int_{0}^{8}dy(8-y)$

$W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)$

$W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})$

$W=450\pi(8*8 -\frac{8^{2}}{2})$

$W=450\pi(64 -\frac{64}{2})$

Therefore, the work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

I hope it helps you!

6 0

3 years ago

Can you solve this? Please ( 15+ points)

Vera_Pavlovna [14]

Answer:

112+24x

Step-by-step explanation:

2(16+(10*4)+(x*12))

solve the inner bracket

2(16+40+12x)

solve this bracket

2(56+12x)

solve this now

112+24x

6 0

2 years ago

Read 2 more answers

Heyo bros i need you're help here.........​

Heyo bros i need you're help here.........