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Alenkinab [10]
3 years ago
5

The most direct way for jonathon to gain on-the-job experience and earn money while attending school is to apply for:

Computers and Technology
2 answers:
boyakko [2]3 years ago
6 0

Answer:

Letter D

Explanation:

Jonathon's most direct way to get a job, gain work experience and make some money while studying for classes is through the work and study program. This program is funded by the United States federal government and approximately 3500 institutions participate.

Importantly, this program works for undergraduate or graduate students.

astraxan [27]3 years ago
5 0
The most direct way for jonathon to gain on-the-job experience and earn money while attending school is to apply for: D:a work-study program
You might be interested in
Prepare a algorithm visualization for the Tower of Hanoi when 4 disks are to be moved from spindle #1 to spindle #3.
Setler [38]

Answer:

follwing is the code for Tower of Hanoi for n disks.

#include <iostream>

using namespace std;

void towofhan(int n,char source,char aux,char dest)//function for tower of hanoi..

{

if(n<0)

return ;

   if(n==1)//base case.

   {

       cout<<"Move disk 1 from "<<source<<" to spindle "<<dest<<endl;

       return;

   }

   towofhan(n-1,source,dest,aux);//recursive call.

   cout<<"move disk "<<n<<" from "<<source<<" to spindle "<<dest<<endl;

   towofhan(n-1,aux,source,dest);//recursive call.

}

int main() {

   int n=4;

   towofhan(n,'1','2','3');//function call.

   return 0;

}

Explanation:

If there is only 1 disk then we have to move the disk from source to destination.

Then after that we will apply recursion to solve the problem.

We have to work on only nth disk else will be done by the recursion.

First call recursion to move n-1 disks from source to auxiliary.

Then move nth disk from source to destination spindle.

Now move n-1 disks that are on the auxiliary spindle to destination spindle.

6 0
3 years ago
True or False. A network is a group of computers that can communicate.
Hunter-Best [27]
The answer is: false
3 0
3 years ago
What is the value of the variable named result after the following code executes?
Makovka662 [10]

Answer:

The value of result is 20

Explanation:

Given

The above code segment

Required

The value of result

In the first line, we have:

X = 5; Y = 3; Z = 2

In the second, we have:

result = (X + Y)/Z * X

This implies that:

result = (5 + 3)/2 * 5

result = 8/2 * 5

result = 4 * 5

result = 20

3 0
3 years ago
A cashier distributes change using the maximum number of five dollar bills, followed by one dollar bills. For example, 19 yields
Alex Ar [27]

Answer:

Written in Python:

dollars = int(input("Amount: "))

numFive = int(dollars/5)

numOnes = dollars%5

print(str(dollars)+" yields "+str(numFive)+" fives and "+str(numOnes)+" ones.")

Explanation:

This line prompts user for input

dollars = int(input("Amount: "))

This line calculates the number of 5 that can be gotten from the input. This is done using integer division

numFive = int(dollars/5)

This line gets the remaining ones. This is done by using the modulo sign to get the remainder when input is divided by 5

numOnes = dollars%5

This line prints the required output

print(str(dollars)+" yields "+str(numFive)+" fives and "+str(numOnes)+" ones.")

4 0
3 years ago
Complete the given C program (prob1.cpp) to read an array of integers, print the array, and find the 2nd largest element in the
labwork [276]

Answer:

#include <stdio.h>

int getElement(int arr[], int size) {

   

   int largest2, largest = 0;

   for(int i=0; i<size; i++)

   {

       if(arr[i] > arr[largest])

       {

           largest = i;

       }

   }

   if(largest != 0)

       largest2 = 0;

   else

       largest2 = size - 1;

   for(int i=0; i<size && i != largest ;i++)

   {

       if(arr[i] > arr[largest2])

           largest2 = i;

   }

   

   return arr[largest2];

}

printArray(int arr[], int size) {

   

   printf("The array is: ");

   for(int i=0; i<size; i++)

   {

       printf("%d ", arr[i]);

   }

   printf("\n");

}

int main()

{

 

   int arr[5] = {30, 20, 5, 10, 24};

   printArray(arr, 5);

   printf("Second largest number is: %d", getElement(arr, 5));

   return 0;

}

Explanation:

Since you did not provide any code, I wrote it from the scratch. I also added the main function for you to check the result.

<em>printArray</em> function basically prints the element of the array

<em>getElement</em> function:

- Declare the two variables to hold the value for largest and second largest

- Inside the first loop, check if there is any number that is greater than largest, if yes, assign it to largest

- Inside the second for loop, check if there is any number that is greater than largest2, if yes, assign it to largest2 (Be aware that the largest we found in the first loop is excluded)

- Return the second largest

* Notice that we were able to apply this solution since the numbers are unique.

5 0
3 years ago
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