The length of a rectangle is 4cm less than twice the width. The perimeter is 58cm. Find the length

1 answer:

6 0

Let x be the width so the length will be 2x-4 . The perimeter can be found by the equation x+x+(2x-4)+(2x-4)=58. Notice I repeated the length and the width twice because you know there are two lengths and two widths in a rectangle, so continue solving by combining like terms 6x-8=58 the add 8 to both sides 6x=66 then divide both sides by 6 to obtain x=11, that's the width but they are asking you for the length so we said the length could be found by the equation 2x-4, now plug in the 11, 2(11)-4 and solve 22-4 equals 18cm which is the length.

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The solutions to the inequality y < to -x+1 sre shaded on the graph. Which point is a solution

Citrus2011 [14]

<h3>Answer: B. (3,-2)</h3>

There are two ways to confirm this is the answer. The first is to note that (3,-2) is on the boundary, so it is part of the solution set. This only works if the boundary line is a solid line (as opposed to a dashed or dotted line).

The second way is to plug (x,y) = (3,-2) into the given inequality to find that

$y \le -x+1\\\\-2 \le -3+1\\\\-2 \le -2$