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defon
3 years ago
11

Omg help what is 2 divided by 5 times 83 to the power of four times -19 plus 1

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

94916624

Step-by-step explanation:

Your equation could be written several different ways.

Mine was: 2/5(5)(83^4)-19+1

If you written it to \frac{2}{(5)(83^4)} -19 + 1, it would be -18

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Yall please help meee
Lady_Fox [76]

Answer:

<u>12n + 2</u>

Step-by-step explanation:

w(n) = un + 2

w(3n) = 4(3n) + 2

ans = 12n + 2

hope it helps you

have a great day!!

6 0
3 years ago
The price of apples is $3.60 for 3 pounds write the price as a unit rate
Finger [1]

Take the total and divide by the amount to get answer.

3.60 /3 = $1.20 per pound

4 0
3 years ago
Help pls and thank you
netineya [11]
A, C, and D are all correct answers, since you are taking away 4 in each of the answers. Hope this helped!
6 0
3 years ago
What is the product of 7/10×(-9)​
Andrews [41]

Answer:

-6.3

Step-by-step explanation:

7/10 X -9/1 = -63/10 = -6.3

4 0
3 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
4 years ago
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