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Varvara68 [4.7K]
4 years ago
12

What is 5/8ths  of 48 , I need help I really don't get it 

Mathematics
2 answers:
Bess [88]4 years ago
6 0
\frac58\ \cdot\ 48=\\=\frac58\ \cdot\ \frac{48}{1}=\\=\frac51\ \cdot\ \frac61=\\=5\ \cdot\ 6=\\=30



uranmaximum [27]4 years ago
6 0
You multiply 5/8 with 48.
The answer will then be 30.
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HELP WITH THESE QUESTIONS PART 2.
polet [3.4K]

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

**********************************************************

Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

6 0
3 years ago
3(5b-1)=5<br> solve for b<br><br> 4(3y-1)=20<br> solve for y
Gnom [1K]
3(5b-1)=5
Get rid of the brackets
15b-3=5
add 3 to both sides of the equation
15b=8
divide both sides of the equation by 15
b=0.53

4(3y-1)=20
12y-4=20
12y=24
y=0.5
7 0
3 years ago
What is 892 to the nearest 100
Olegator [25]
I’m pretty sure This rounds to 900
3 0
3 years ago
Read 2 more answers
Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π
lorasvet [3.4K]

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The <em>instantaneous</em> rate of change at a given value of x can be found by concept of derivative, which is described below:

g(x) =  \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

Where h is the <em>difference</em> rate.

In this question we must find an expression for the <em>instantaneous</em> rate of change of g if f(x) = \sin x and evaluate the resulting expression for x = \frac{\pi}{3}. Then, we have the following procedure below:

g(x) =  \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}

g(x) =  \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}

g(x) =  \lim_{h \to 0} \frac{\sin h}{h}\cdot  \lim_{h \to 0} \cos x

g(x) = \cos x

Now we evaluate g(x) for x = \frac{\pi}{3}:

g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>. \blacksquare

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

4 0
2 years ago
What is the value marginal product of labor if p = $10, mpl = $25, and apl = 40? multiple choice $400 $10,000 $250 $1,000
ioda

If P=$10, MPL= $25 and APL=$ 40, then the value of marginal product of labor is $250

The marginal product of labor (MPL) is the change in output that results from employing an added unit of labor.

The average product of labor (APL) is the total product of labor divided by the number of units of labor employed.

Here,

P= $10

The marginal product of labor (MPL)= $25

The average product of labor (APL)= $40

The value of marginal product of labor= P × The marginal product of labor (MPL)

The value of marginal product of labor= 10×25=$250

Hence, If P=$10, MPL= $25 and APL=$ 40, then the value of marginal product of labor is $250

Learn more about the value of marginal product of labor here

brainly.com/question/15072173

#SPJ4

3 0
1 year ago
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