Answer:
g(x) - f(x) = -14x - 3
Step-by-step explanation:
We need to subtract the function f(x) = 9x + 4 from the function g(x) = -5 + 1. Rewriting these two functions in columns, we get
g(x)= -5x+1
- f(x) = -(9x+4) Note: Use parentheses as shown here.
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g(x) - f(x) = -14x - 3
Your answer would be $1.89
You take 11.34 and divide it by 6. After that you’ll be 1.89 as your unit price.
1.89 is how much for 1 pound
Answer:
A) 991=43x+475
B) 12 hours
Step-by-step explanation:
Answer:
The rational number equivalent to 3.24 repeating is 321/99
Step-by-step explanation:
To convert the decimal number to a rational number we can state this number and its multiples of 10, trying to find two number with identical decimal parts:
n=3.24242424...
10n=32.4242424....
100n=324.2424242...
Now, 100n and n have the same decimal part, then by subtracting these numbers we obtain:
100n-n=324.24242424...-3.24242424... = 321
99n = 321
n = 321/99
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.