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3 years ago

15

Swimsuit discounted 65% on sale for $20.30

1 answer:

tigry1 [53]3 years ago

6 0

Hello there!

Knowing that you have a swimsuit of an original price of $20.30 that is discounted 65%, you can find the price of the swimsuit after the discount by first finding 65% of your original price.

To find 65% of your original price, multiply 65% to 20.30:
0.65*20.30
=13.195

Now, subtract this amount from your original price:
20.30-13.195
=7.105

Finally, round to the nearest cent to get $7.11 dollars as your final answer.

Hope this helps and have a marvelous day! :)

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Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

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Substitute into the first equation to solve for x .

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Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

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$( \frac{2}{3} , \frac{1}{5} )$

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