All categories

3 years ago

Suppose that $9500 is placed in an account that pays 8% interest compounded each year.

1 answer:

6 0

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}$

You might be interested in

Prove that

Dovator [93]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

secx = $\frac{1}{cosx}$ , cosecx = $\frac{1}{sinx}$

cotx = $\frac{cosx}{sinx}$ , tanx = $\frac{sinx}{cosx}$

Consider the left side

secA cosecA - cotA

= $\frac{1}{cosA}$ × $\frac{1}{sinA}$ - $\frac{cosA}{sinA}$

= $\frac{1}{cosAsinA}$ - $\frac{cosA}{sinA}$

= $\frac{1-cos^2A}{cosAsinA}$

= $\frac{sin^2A}{cosAsinA}$ ( cancel sinA on numerator/ denominator )

= $\frac{sinA}{cosA}$

= tanA = right side ⇒ proven

5 0

3 years ago

Write an equation of the line perpendicular to the line 8x+15y=12 and containing the point (11,17) write the answer in standard

jek_recluse [69]

The slope of a line perpendicular to another line has a slope which is the negative reciprocal of that line or:

m1 = -1/m2

First, we convert the given equation into slope-intercept form of a line: y = mx + b

8x + 15y = 12

15y = -8x + 12

y = (-8/15) x + 0.8

m1 = -8 / 15

Therefore the slope of the perpendicular line is:

m2 = 15 / 8

Since the perpendicular line crosses the point (11, 17), therefore using the slope formula:

m = (y2 – y1) / (x2 – x1)

15 / 8 = (y2 – 17) / (x2 – 11)

1.875 (x2 – 11) = y2 – 17

1.875 x2 – 20.625 = y2 – 17

y2 = 1.875 x2 – 3.625

y = (15/8) x – 3.625

multiplying both sides by 8:

8y = 15x – 29

rewriting in standard form:

<span>15x – 8y = 29 (ANSWER)</span>

3 0

3 years ago

a rectangular plot of land 8m long and 6m wide.there is a flower bed in the form of a circle of radius 3m.find 1.area of land. 2

mixer [17]

Answer:

1)Area of the Land is 48 square meters

2) Area of flower bed is 28.26 square meter

3)Area of land excluding flower bed is 19.74 square meters

4)cost of planting grass in land excluding flower bed is Rs 118.44

Step-by-step explanation:

Given:

Length of the Rectangular plot = 8m

Width of the rectangular plot = 6m

Radius of the circular flower bed = 3m

1)Area of the Land

Area of the Rectangular plot = Area of the Land

Area of the Land = length x width

Area of the Land = 8*6

Area of the Land = 48 square meters-----------------------------(1)

2. Area of flower bed

Area of flower bed = 4 x area of one quadrant

Area of flower bed = area of the circle

Area of flower bed = $\pi r^2$

where r is the radius

Now , substituting the values

Area of flower bed = $\pi (3)(3)$

Area of flower bed = 28.26 square meters-----------------------------(2)

3)Area of land excluding flower bed

Area of land excluding flower bed = Area of the rectangular land - area of flower beds

Area of land excluding flower bed = 48 - 28.26

Area of land excluding flower bed = 19.74 square meters

4)cost of planting grass in land

Cost of planting grass per square meter = 6

Excluding the flower bed we have 19.74 square meters. to plant grass for this 19. 74 square meters, the cost will be

= $19. 74 \times 6$

= Rs 118.44

6 0

3 years ago

Mr. Evan is paid $9.20 per hour for the first 40 hours he works in a week he is paid 1.5 times that rate for each hour after tha

faust18 [17]

That is incorrect. The correct answer should be $398.38
First you take 9.2 times 40 and you get $368 which is how much he got paid for the first 40 hours. now he worked 2.25 hours extra so you take 9.2 * 1.5 because he gets 1.5 times more for extra hours. Then you add that to the $368 and you get $398.38

7 0

3 years ago

Consider the following pair of equations:

Zinaida [17]

Answer:

The lines representing these equations intercept at the point (-4,2) on the plane.

Step-by-step explanation:

When we want to find were both lines intercept, we are trying to find a pair of values (x,y) that belongs to both equations, which means that it satisfies both equations at the same time.

Therefore, we can use the second equation that gives us the value of y in terms of x, to substitute for y in the first equation. Then we end up with an equation with a unique unknown, for which we can solve:

$x+y=-2\\x+(2x+10)=-2\\x+2x+10=-2\\3x+10=-2\\3x=-2-10\\3x=-12\\x=\frac{-12}{3} \\x=-4$

Next we use this value we obtained for x (-4) in the same equation we use for substitution in order to find which y value corresponds to this:

$y=2x+10\\y=2(-4)+10\\y=-8+10\\y=2$

Then we have the pair (x,y) that satisfies both equations (-4,2), which is therefore the point on the plane where both lines intercept.

5 0

3 years ago