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2 years ago

The product of two and a number, divided by five

Mathematics

1 answer:

DENIUS [597]2 years ago

4 0

Question: the product of two and a number, divided by five

Let the number be 'a'.

Answer: 2a/5

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2 years ago

Read 2 more answers

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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3 years ago

How could you find the area of the pink title? Choose all that apply.

DaniilM [7]

By using green to find the pink locate all the ponies

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2 years ago

Can someone please help me with 4 and 5 ???

Montano1993 [528]

Answer:

4. D

A: -25.5=a

B: b=-4

C: c=12

D: d=8

Step-by-step explanation:

4.Between a and d they are the 2 bigger values but D was the greatest out of all of them. - divided by a - will result as a positive and 7/9=0.77 and 19/12 *I looked for the least common factor and multiplied numerator and denominator to 12 depending on the denominators value. Ex: since one of my denominators was 4, I multiply the whole fraction by 3 to get 9/12 and the other was 5/6 times 2 is 10/12 and just add 10/12 by 9/12 which is 19/12.

A: All I did was multiply 8.5 and -3 and get -25.5=a.

B: I add 7 on both sides of the equation and -7 and 7 get canceled off and -11+7=-4. b=4.

C: I multiplied - to -3 and got 3, now I can subtract -3 on both sides. 15-3=12 so c=12.

D. I had to divide by 4 on both sides to get d by itself. 32/4=8 so final answer would be d=8.

5 0

3 years ago