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3 years ago

Simplify the following expression in your notebook. Select the correct answer.

Mathematics

2 answers:

Archy [21]3 years ago

6 0

-24n2+31 if im correct!

OleMash [197]3 years ago

3 0

Answer:

$-24n^2 + 31$

Step-by-step explanation:

$7 - 3[(n^3 + 8n) divide (-n) + 9n^2]$

To simplify it we use order of operation PEMDAS

Parenthesis , exponents , multiply, divide, add and subtract

$7 - 3[(n^3+ 8n) divide (-n) + 9n^2]$

LEts start with parenthesis (divide by -n)

$7 - 3[-n^2-8+ 9n^2]$

Now we simplify the parenthesis by combining like terms

$7 - 3[-8+8n^2]$

multiply by -3

$7+24 -24n^2$

$-24n^2 + 31$

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Conditional tree diagram

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Answer:

The first one would be 3/5, the top one in the second branch would be 1/5 and the bottom one would be 3/5. You get to this answer by subtracting 1-(the fraction you already have).

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2 years ago

At a preschool 16 of the students are four years old of a four year olds 3/8 attended the full day program how many other studen

Nikitich [7]

Answer:

6 students at the preschool of four years old attended the full day program.

Step-by-step explanation:

Given:

Number of four years old students = 16

fraction of four years old students attended full day program = $\frac{3}{8}$

We need to find the number of four years old students attended the full day program.

Solution:

Now we can say that;

number of four years old students attended the full day program is equal to fraction of four years old students attended full day program multiplied by Number of four years old students.

framing in equation form we get;

number of four years old students attended the full day program = $\frac38\times 16 =6$

Hence 6 students at the preschool of four years old attended the full day program.

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2 years ago

Write a sentence to compare 1000000 using the words 10 times as many

erik [133]

You can write 1000000 is 10 times as many then 100000

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3 years ago

Help please!! don’t know what to do?!

arlik [135]

Answer:

Step-by-step explanation:

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2 years ago

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers