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3 years ago

Simplify the following expression in your notebook. Select the correct answer.

Mathematics

2 answers:

Archy [21]3 years ago

6 0

-24n2+31 if im correct!

OleMash [197]3 years ago

3 0

Answer:

$-24n^2 + 31$

Step-by-step explanation:

$7 - 3[(n^3 + 8n) divide (-n) + 9n^2]$

To simplify it we use order of operation PEMDAS

Parenthesis , exponents , multiply, divide, add and subtract

$7 - 3[(n^3+ 8n) divide (-n) + 9n^2]$

LEts start with parenthesis (divide by -n)

$7 - 3[-n^2-8+ 9n^2]$

Now we simplify the parenthesis by combining like terms

$7 - 3[-8+8n^2]$

multiply by -3

$7+24 -24n^2$

$-24n^2 + 31$

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Can someone help me with this i don’t understand at all

Sedbober [7]

Answer:

Use trig

Step-by-step explanation:

sin(55) = x/21

x = 21sin(55)

use calculator in degree mode

cos(55) = y/21

21cos(55) = y

5 0

2 years ago

A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

3 years ago

Try to fill in the missing numbers

GrogVix [38]

9514 1404 393

Answer:

[[274][895][136]]

Step-by-step explanation:

Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.

The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.

There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.

The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.

Our solution is ...

row 1: 2 + 7 × 4 = 30

row 2: 8 + 9 × 5 = 53

row 3: 1 × 3 - 6 = -3

And that makes the column equations be ...

col 1: 2 - 8 + 1 = -5

col 2: 7 + 9 / 3 = 10

col 3: 4 × 5 - 6 = 14

6 0

3 years ago

Answer? with solution please. Will automatically report kung wala:)

serious [3.7K]

Answer:

Step-by-step explanation:

Communitive only works with multiplication and addition. It states that if you have something adding or subtracting something switched around, they are the same. B has that so the answer is B

Can I have Brainliest?

4 0

3 years ago

Hey can someone pls pls pls help me asap?!

PilotLPTM [1.2K]

I don’t know 16 wiry ends sh

8 0

3 years ago